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Poultry should be cooked to a temperature of 
75^(@)C. A chicken is removed from the oven and left to rest in a room that is at a constant temperature of 
22^(@)C. The temperature of the chicken 
t hours after it is removed from the oven is given by the exponential function:

T(t)=22+53(0.74)^(t)
What is the approximate temperature of the chicken after 2 hours?
Choose 1 answer:
(A) 
22^(@)C
(B) 
51^(@)C
(c) 
74^(@)C
(D) 
75^(@)C

Poultry should be cooked to a temperature of 75C 75^{\circ} \mathrm{C} . A chicken is removed from the oven and left to rest in a room that is at a constant temperature of 22C 22^{\circ} \mathrm{C} . The temperature of the chicken t t hours after it is removed from the oven is given by the exponential function:\newlineT(t)=22+53(0.74)t T(t)=22+53(0.74)^{t} \newlineWhat is the approximate temperature of the chicken after 22 hours?\newlineChoose 11 answer:\newline(A) 22C 22^{\circ} \mathrm{C} \newline(B) 51C 51^{\circ} \mathrm{C} \newline(C) 74C 74^{\circ} \mathrm{C} \newline(D) 75C 75^{\circ} \mathrm{C}

Full solution

Q. Poultry should be cooked to a temperature of 75C 75^{\circ} \mathrm{C} . A chicken is removed from the oven and left to rest in a room that is at a constant temperature of 22C 22^{\circ} \mathrm{C} . The temperature of the chicken t t hours after it is removed from the oven is given by the exponential function:\newlineT(t)=22+53(0.74)t T(t)=22+53(0.74)^{t} \newlineWhat is the approximate temperature of the chicken after 22 hours?\newlineChoose 11 answer:\newline(A) 22C 22^{\circ} \mathrm{C} \newline(B) 51C 51^{\circ} \mathrm{C} \newline(C) 74C 74^{\circ} \mathrm{C} \newline(D) 75C 75^{\circ} \mathrm{C}
  1. Identify function and value: Identify the given function and the value to be substituted.\newlineThe temperature function is given by T(t)=22+53(0.74)tT(t) = 22 + 53(0.74)^t. We need to find the temperature after 22 hours, so we will substitute t=2t = 2 into the function.
  2. Substitute value into function: Substitute t=2t = 2 into the function to find T(2)T(2).\newlineT(2)=22+53(0.74)2T(2) = 2^2 + 53(0.74)^2
  3. Calculate exponent: Calculate the value of (0.74)2(0.74)^2.\newline(0.74)2=0.5476(0.74)^2 = 0.5476 (rounded to four decimal places for precision)
  4. Multiply by constant: Multiply 5353 by 0.54760.5476.\newline53×0.5476=29.022853 \times 0.5476 = 29.0228
  5. Add to initial value: Add 2222 to the result from Step 44 to find T(2)T(2). \newlineT(2)=22+29.0228T(2) = 22 + 29.0228\newlineT(2)=51.0228T(2) = 51.0228
  6. Round to nearest whole number: Round the result to the nearest whole number to match the answer choices.\newlineT(2)51CT(2) \approx 51^{\circ}C

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