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P(t)=20(0.95)^(t) The function models P, the population of Leetown in thousands, t years after 2007 . What was the population of Leetown in 2007 ? Choose 1 answer: A 5 thousand (B) 19 thousand (C) 20 thousand (D) 95 thousand

P(t)=20(0.95)t P(t)=20(0.95)^{t} \newlineThe function models P P , the population of Leetown in thousands, t t years after 20072007 . What was the population of Leetown in 20072007 ?\newlineChoose 11 answer:\newline(A) 55 thousand\newline(B) 1919 thousand\newline(C) 2020 thousand\newline(D) 9595 thousand

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Q. P(t)=20(0.95)t P(t)=20(0.95)^{t} \newlineThe function models P P , the population of Leetown in thousands, t t years after 20072007 . What was the population of Leetown in 20072007 ?\newlineChoose 11 answer:\newline(A) 55 thousand\newline(B) 1919 thousand\newline(C) 2020 thousand\newline(D) 9595 thousand
  1. Identify Initial Population: The function P(t)=20(0.95)tP(t) = 20(0.95)^t models the population of Leetown in thousands, tt years after 20072007. To find the population in 20072007, we need to evaluate P(t)P(t) at t=0t = 0, since tt represents the number of years after 20072007.
  2. Substitute t=0t = 0: Substitute t=0t = 0 into the function to find the initial population P(0)P(0).\newlineP(0)=20(0.95)0P(0) = 20(0.95)^0
  3. Calculate P(0)P(0): Since any number raised to the power of 00 is 11, we have:\newlineP(0)=20×1P(0) = 20 \times 1
  4. Perform Multiplication: Perform the multiplication to find the population in 20072007. P(0)=20P(0) = 20
  5. Population in 20072007: The population of Leetown in 20072007 was 2020 thousand.

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