Let f(x)=(3)/(4)x+10 and g(x)=x^(2)-3. What is the value of f(-2-g(3)) ?

Given Functions: We are given two functions: f(x) = (3/4)x + 10 g(x) = x^2 - 3 We need to find the value of f(-2 - g(3)). First, we will calculate g(3). Substitute x = 3 into g(x). g(3) = 3^2 - 3Calculate g(3): Calculate the value of g(3). g(3) = 3^2 - 3 g(3) = 9 - 3 g(3) = 6 Now we have the value of g(3).Substitute g(3): Next, we will substitute g(3) into the expression -2 - g(3). -2 - g(3) = -2 - 6Calculate -2 - g(3): Calculate the value of -2 - g(3). -2 - g(3) = -2 - 6 -2 - g(3) = -8 Now we have the value of -2 - g(3).Substitute -8 into f(x): Finally, we will substitute -8 into f(x) to find f(-2 - g(3)). f(-8) = (3/4)(-8) + 10Calculate f(-8): Calculate the value of f(-8). f(-8) = (3/4)(-8) + 10 f(-8) = -6 + 10 f(-8) = 4 Now we have the value of f(-2 - g(3)).

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Let
f(x)=(3)/(4)x+10 and
g(x)=x^(2)-3. What is the value of
f(-2-g(3)) ?

Let $f(x)=\frac{3}{4} x+10$ and $g(x)=x^{2}-3$ . What is the value of $f(-2-g(3))$ ?

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Algebra 1

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Q. Let

f(x)=\frac{3}{4} x+10

and

g(x)=x^{2}-3

. What is the value of

f(-2-g(3))

Given Functions: We are given two functions: $\newline$ $f(x) = \frac{3}{4}x + 10$ $\newline$ $g(x) = x^2 - 3$ $\newline$ We need to find the value of $f(-2 - g(3))$ . $\newline$ First, we will calculate $g(3)$ . $\newline$ Substitute $x = 3$ into $g(x)$ . $\newline$ $g(3) = 3^2 - 3$
Calculate $g(3)$ : Calculate the value of $g(3)$ .
$g(3) = 3^2 - 3$
$g(3) = 9 - 3$
$g(3) = 6$
Now we have the value of $g(3)$ .
Substitute $g(3)$ : Next, we will substitute $g(3)$ into the expression $-2 - g(3)$ . $\newline$ $-2 - g(3) = -2 - 6$
Calculate $-2 - g(3)$ : Calculate the value of $-2 - g(3)$ .
$-2 - g(3) = -2 - 6$
$-2 - g(3) = -8$
Now we have the value of $-2 - g(3)$ .
Substitute $-8$ into $f(x)$ : Finally, we will substitute $-8$ into $f(x)$ to find $f(-2 - g(3))$ . $\newline$ $f(-8) = (\frac{3}{4})(-8) + 10$
Calculate $f(-8)$ : Calculate the value of $f(-8)$ .
$f(-8) = \frac{3}{4}(-8) + 10$
$f(-8) = -6 + 10$
$f(-8) = 4$
Now we have the value of $f(-2 - g(3))$ .