Q. Is the following function even, odd, or neither?f(x)=2x+3Choose 1 answer:(A) Even(B) Odd(C) Neither
Symmetry properties of the function: To determine if the function f(x)=2(x+3) is even, odd, or neither, we need to check the symmetry properties of the function. An even function satisfies f(x)=f(−x) for all x in its domain, and an odd function satisfies f(−x)=−f(x) for all x in its domain.
Checking if f(x) is even: Let's first check if f(x) is even. We need to compare f(x) with f(-x). We have f(x) = 2(x+3). Now let's find f(-x) which is f(-x) = 2(−x+3).
Comparing f(x) with f(−x): Now we compare f(x) with f(−x). If f(x)=f(−x) for all x, then the function is even. We have f(x)=2(x+3) and f(−x)=2(−x+3). These two expressions are not equal for all x because the exponents are not the same due to the sign change in x. Therefore, f(x) is not an even function.
Conclusion: f(x) is not an even function: Next, let's check if f(x) is odd. For f(x) to be odd, we need f(−x) to be equal to −f(x) for all x. We already have f(−x)=2−x+3. Now let's find −f(x) which is −f(x)=−2x+3.
Checking if f(x) is odd: We compare f(−x) with −f(x). If f(−x)=−f(x) for all x, then the function is odd. We have f(−x)=2−x+3 and −f(x)=−2x+3. These two expressions are not equal for all x because the negative sign outside the exponent does not change the exponent itself. Therefore, f(x) is not an odd function.
Comparing f(−x) with −f(x): Since f(x) is neither even nor odd, the correct choice is (C) Neither.
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