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If y=(x^(2)-1)(x+4)-9, what is the value of y when x=1 ? Choose 1 answer: (A) -9 (B) -5 (C) -4 (D) 0

If y=(x2−1)(x+4)−9 y=\left(x^{2}-1\right)(x+4)-9 , what is the value of y y when x=1 x=1 ?\newlineChoose 11 answer:\newline(A) −9-9\newline(B) −5-5\newline(C) −4-4\newline(D) 00

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Q. If y=(x2−1)(x+4)−9 y=\left(x^{2}-1\right)(x+4)-9 , what is the value of y y when x=1 x=1 ?\newlineChoose 11 answer:\newline(A) −9-9\newline(B) −5-5\newline(C) −4-4\newline(D) 00
  1. Substitute x=1x=1: First, we need to substitute x=1x=1 into the function y=(x2−1)(x+4)−9y=(x^{2}-1)(x+4)-9 to find the value of yy.
  2. Calculate x2−1x^{2}-1: Calculate the value of x2−1x^{2}-1 when x=1x=1.\newlinex2−1=(1)2−1=1−1=0x^{2}-1 = (1)^{2}-1 = 1-1 = 0
  3. Calculate x+4x+4: Calculate the value of x+4x+4 when x=1x=1.\newlinex+4=1+4=5x+4 = 1+4 = 5
  4. Multiply results: Now, multiply the results from the previous steps: x^{2}-1)(x+4)\. Since \$x^{2}-1 is 00, the product will be 00 regardless of the value of x+4x+4. $0 \times 5 = 0
  5. Subtract 99: Finally, subtract 99 from the result of the multiplication to find the value of yy.\newliney=0−9=−9y = 0 - 9 = -9

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