Q. If y=(x2−1)(x+4)−9, what is the value of y when x=1 ?Choose 1 answer:(A) −9(B) −5(C) −4(D) 0
Substitute x=1: First, we need to substitute x=1 into the function y=(x2−1)(x+4)−9 to find the value of y.
Calculate x2−1: Calculate the value of x2−1 when x=1.x2−1=(1)2−1=1−1=0
Calculate x+4: Calculate the value of x+4 when x=1.x+4=1+4=5
Multiply results: Now, multiply the results from the previous steps: x^{2}-1)(x+4)\. Since \$x^{2}-1 is 0, the product will be 0 regardless of the value of x+4. $0 \times 5 = 0
Subtract 9: Finally, subtract 9 from the result of the multiplication to find the value of y.y=0−9=−9
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