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If y=(4x-1)(x+1)(x+2)+5", " what is the value of y when x=-1" ? "

If y=(4x−1)(x+1)(x+2)+5y=(4 x-1)(x+1)(x+2)+5 , what is the value of y y when x=−1 ? x=-1 \text { ? }

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Q. If y=(4x−1)(x+1)(x+2)+5y=(4 x-1)(x+1)(x+2)+5 , what is the value of y y when x=−1 ? x=-1 \text { ? }
  1. Substitute x=−1x=-1: We need to substitute x=−1x=-1 into the expression y=(4x−1)(x+1)(x+2)+5y=(4x-1)(x+1)(x+2)+5 and simplify.\newlineSubstitute x=−1x=-1 into the expression:\newliney=(4(−1)−1)((−1)+1)((−1)+2)+5y=(4(-1)-1)((-1)+1)((-1)+2)+5
  2. Calculate value of terms: Now, calculate the value of each term:\newline4(−1)=−44(-1) = -4\newline−4−1=−5-4 - 1 = -5\newline(−1)+1=0(-1) + 1 = 0\newline(−1)+2=1(-1) + 2 = 1
  3. Multiply terms and simplify: Next, multiply the terms together:\newliney=(−5)(0)(1)+5y=(-5)(0)(1)+5\newlineSince any number multiplied by zero is zero, the product of the first three terms will be zero.\newliney=0+5y=0+5
  4. Add 55 to product: Finally, add 55 to the product:\newliney=5y=5

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