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If 
p > 0 and 
(p^(m))^(2n)*(p^(2m))^(n)=16^(mn), then what is the value of 
p ?

If p>0 and (pm)2n(p2m)n=16mn \left(p^{m}\right)^{2 n} \cdot\left(p^{2 m}\right)^{n}=16^{m n} , then what is the value of p p ?

Full solution

Q. If p>0 p>0 and (pm)2n(p2m)n=16mn \left(p^{m}\right)^{2 n} \cdot\left(p^{2 m}\right)^{n}=16^{m n} , then what is the value of p p ?
  1. Simplify left side of equation: We are given the equation (pm)2n(p2m)n=16mn(p^{m})^{2n}\cdot(p^{2m})^{n}=16^{mn} and we need to find the value of pp. \newlineFirst, we simplify the left side of the equation using the power of a power rule, which states that (ab)c=abc(a^{b})^{c} = a^{b\cdot c}. \newline(pm)2n=pm2n=p2mn(p^{m})^{2n} = p^{m\cdot 2n} = p^{2mn} \newline(p2m)n=p2mn=p2mn(p^{2m})^{n} = p^{2m\cdot n} = p^{2mn} \newlineNow we multiply the two terms together. \newlinep2mnp2mn=p2mn+2mn=p4mnp^{2mn} \cdot p^{2mn} = p^{2mn + 2mn} = p^{4mn}
  2. Simplify right side of equation: Next, we simplify the right side of the equation.\newline16mn16^{mn} can be written as (24)mn(2^4)^{mn} because 1616 is 22 raised to the power of 44.\newline(24)mn=24mn=24mn(2^4)^{mn} = 2^{4\cdot mn} = 2^{4mn}
  3. Solve for pp: Equate left and right side of equation to solve for pp. \newlineNow we have the equation p4mn=24mnp^{4mn} = 2^{4mn}. \newlineSince the exponents of pp and 22 are the same, we can equate the bases. p=2p = 2

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