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If h(x)=(1)/(x^(2)-1), what is the value of h(3) ? Choose 1 answer: (A) (1)/(8) (B) (1)/(4) (C) (1)/(3) (D) (1)/(2)

If h(x)=1x2−1 h(x)=\frac{1}{x^{2}-1} , what is the value of h(3) h(3) ?\newlineChoose 11 answer:\newline(A) 18 \frac{1}{8} \newline(B) 14 \frac{1}{4} \newline(C) 13 \frac{1}{3} \newline(D) 12 \frac{1}{2}

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Full solution

Q. If h(x)=1x2−1 h(x)=\frac{1}{x^{2}-1} , what is the value of h(3) h(3) ?\newlineChoose 11 answer:\newline(A) 18 \frac{1}{8} \newline(B) 14 \frac{1}{4} \newline(C) 13 \frac{1}{3} \newline(D) 12 \frac{1}{2}
  1. Substitute xx with 33: To find the value of h(3)h(3), we need to substitute xx with 33 in the function h(x)=1x2−1h(x)=\frac{1}{x^{2}-1}.\newlineh(3)=1(3)2−1h(3) = \frac{1}{(3)^{2} - 1}
  2. Perform calculation inside parentheses: Now we perform the calculation inside the parentheses.\newline(3)2−1=9−1=8(3)^2 - 1 = 9 - 1 = 8
  3. Substitute result back into function: Next, we substitute the result back into the function to find h(3)h(3). \newlineh(3)=18h(3) = \frac{1}{8}
  4. Value of h(3)h(3) matches: We can see that the value of h(3)h(3) matches one of the given choices, which is (A) 18\frac{1}{8}.

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