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If 
g(x)=2x^(2)+x, what is the value of 
g((1)/(2)) ?
Choose 1 answer:
(A) 
(1)/(2)
(B) 1
(C) 
(3)/(2)
(D) 
(5)/(2)

If g(x)=2x2+x g(x)=2 x^{2}+x , what is the value of g(12) g\left(\frac{1}{2}\right) ?\newlineChoose 11 answer:\newline(A) 12 \frac{1}{2} \newline(B) 11\newline(C) 32 \frac{3}{2} \newline(D) 52 \frac{5}{2}

Full solution

Q. If g(x)=2x2+x g(x)=2 x^{2}+x , what is the value of g(12) g\left(\frac{1}{2}\right) ?\newlineChoose 11 answer:\newline(A) 12 \frac{1}{2} \newline(B) 11\newline(C) 32 \frac{3}{2} \newline(D) 52 \frac{5}{2}
  1. Substitute xx in g(x)g(x): Substitute (1/2)(1/2) for xx in the function g(x)=2x2+xg(x) = 2x^2 + x.\newlineg((1/2))=2((1/2)2)+(1/2)g((1/2)) = 2((1/2)^2) + (1/2)
  2. Calculate square of (1/2)(1/2): Calculate the square of (1/2)(1/2).(1/2)2=(12)/(22)=1/4(1/2)^2 = (1^2)/(2^2) = 1/4
  3. Multiply 22 and result: Multiply 22 by the result from Step 22.\newline2×(14)=24=122 \times (\frac{1}{4}) = \frac{2}{4} = \frac{1}{2}
  4. Add result to (12)(\frac{1}{2}): Add the result from Step 33 to (12)(\frac{1}{2}).12+12=22=1\frac{1}{2} + \frac{1}{2} = \frac{2}{2} = 1

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