If (P+R)/(2)=8, which of the following correctly gives R in terms of P ? Choose 1 answer: (A) R=16+P (B) R=16-P (C) R=8-(P)/(2) (D) R=4-P

Rephrase the Problem: First, let's rephrase the ＂What is the value of R in terms of P if (P+R)/2 equals 8?＂Multiply by 2: We are given the equation (P+R)/2 = 8. To find R in terms of P, we need to isolate R on one side of the equation. Let's start by multiplying both sides of the equation by 2 to eliminate the denominator. 2 * ((P+R)/2) = 2 * 8Isolate R: After multiplying both sides by 2, we get: P + R = 16 Now, we need to isolate R by subtracting P from both sides of the equation.Subtract P: Subtracting P from both sides gives us: R = 16 - P This is the expression for R in terms of P.

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If
(P+R)/(2)=8, which of the following correctly gives
R in terms of
P ?
Choose 1 answer:
(A)
R=16+P
(B)
R=16-P
(C)
R=8-(P)/(2)
(D)
R=4-P

If $\frac{P+R}{2}=8$ , which of the following correctly gives $R$ in terms of $P$ ? $\newline$ Choose $1$ answer: $\newline$ (A) $R=16+P$ $\newline$ (B) $R=16-P$ $\newline$ (C) $R=8-\frac{P}{2}$ $\newline$ (D) $R=4-P$

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Math Problems

Algebra 1

Compare linear and exponential growth

Full solution

Q. If

\frac{P+R}{2}=8

, which of the following correctly gives

R

in terms of

P

\newline

Choose

1

answer:

\newline

(A)

R=16+P

\newline

(B)

R=16-P

\newline

(C)

R=8-\frac{P}{2}

\newline

(D)

R=4-P

Rephrase the Problem: First, let's rephrase the ＂What is the value of $R$ in terms of $P$ if $(P+R)/2$ equals $8$ ?＂
Multiply by $2$ : We are given the equation $(P+R)/2 = 8$ . To find $R$ in terms of $P$ , we need to isolate $R$ on one side of the equation. Let's start by multiplying both sides of the equation by $2$ to eliminate the denominator. $\newline$ $2 \times ((P+R)/2) = 2 \times 8$
Isolate R: After multiplying both sides by $2$ , we get: $P + R = 16$ Now, we need to isolate $R$ by subtracting $P$ from both sides of the equation.
Subtract $P$ : Subtracting $P$ from both sides gives us: $\newline$ $R = 16 - P$ $\newline$ This is the expression for $R$ in terms of $P$ .