If 2x^(2)-7x-5=0, what are the values of x ? Choose 1 answer: (A) 1 and (5)/(2) (B) (7)/(4)-(sqrt89)/(4) and (7)/(4)+(sqrt89)/(4) (C) (7)/(2)-(sqrt69)/(2) and (7)/(2)+(sqrt69)/(2) (D) (7)/(2)-(sqrt89)/(2) and (7)/(2)+(sqrt89)/(2)

Use Quadratic Formula: Use the quadratic formula x = (-b ± √(b^2 - 4ac)) / (2a) where a = 2, b = -7, and c = -5.Calculate Discriminant: Calculate the discriminant b^2 - 4ac = (-7)^2 - 4(2)(-5) = 49 + 40 = 89.Plug into Formula: Plug the discriminant into the quadratic formula: x = (7 ± √89) / (2*2).Simplify Expression: Simplify the expression: x = (7 ± √89) / 4.Find Solutions: The solutions are x = (7/4) - (√89)/4 and x = (7/4) + (√89)/4.

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If
2x^(2)-7x-5=0, what are the values of
x ?
Choose 1 answer:
(A) 1 and
(5)/(2)
(B)
(7)/(4)-(sqrt89)/(4) and

(7)/(4)+(sqrt89)/(4)
(C)
(7)/(2)-(sqrt69)/(2) and

(7)/(2)+(sqrt69)/(2)
(D)
(7)/(2)-(sqrt89)/(2) and

(7)/(2)+(sqrt89)/(2)

If $2 x^{2}-7 x-5=0$ , what are the values of $x$ ? $\newline$ Choose $1$ answer: $\newline$ (A) $1$ and $\frac{5}{2}$ $\newline$ (B) $\frac{7}{4}-\frac{\sqrt{89}}{4}$ and $\newline$ $\frac{7}{4}+\frac{\sqrt{89}}{4}$ $\newline$ (C) $\frac{7}{2}-\frac{\sqrt{69}}{2}$ and $\newline$ $\frac{7}{2}+\frac{\sqrt{69}}{2}$ $\newline$ (D) $\frac{7}{2}-\frac{\sqrt{89}}{2}$ and $\newline$ $\frac{7}{2}+\frac{\sqrt{89}}{2}$

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Math Problems

Algebra 1

Compare linear and exponential growth

Full solution

Q. If

2 x^{2}-7 x-5=0

, what are the values of

x

\newline

Choose

1

answer:

\newline

(A)

1

and

\frac{5}{2}

\newline

(B)

\frac{7}{4}-\frac{\sqrt{89}}{4}

and

\newline

\frac{7}{4}+\frac{\sqrt{89}}{4}

\newline

(C)

\frac{7}{2}-\frac{\sqrt{69}}{2}

and

\newline

\frac{7}{2}+\frac{\sqrt{69}}{2}

\newline

(D)

\frac{7}{2}-\frac{\sqrt{89}}{2}

and

\newline

\frac{7}{2}+\frac{\sqrt{89}}{2}

Use Quadratic Formula: Use the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ where $a = 2$ , $b = -7$ , and $c = -5$ .
Calculate Discriminant: Calculate the discriminant $b^2 - 4ac = (-7)^2 - 4(2)(-5) = 49 + 40 = 89$ .
Plug into Formula: Plug the discriminant into the quadratic formula: $x = \frac{7 \pm \sqrt{89}}{2 \cdot 2}$ .
Simplify Expression: Simplify the expression: $x = \frac{7 \pm \sqrt{89}}{4}$ .
Find Solutions: The solutions are $x = \frac{7}{4} - \frac{\sqrt{89}}{4}$ and $x = \frac{7}{4} + \frac{\sqrt{89}}{4}$ .