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If 
2x^(2)-7x-5=0, what are the values of 
x ?
Choose 1 answer:
(A) 1 and 
(5)/(2)
(B) 
(7)/(4)-(sqrt89)/(4) and

(7)/(4)+(sqrt89)/(4)
(C) 
(7)/(2)-(sqrt69)/(2) and

(7)/(2)+(sqrt69)/(2)
(D) 
(7)/(2)-(sqrt89)/(2) and

(7)/(2)+(sqrt89)/(2)

If 2x27x5=0 2 x^{2}-7 x-5=0 , what are the values of x x ?\newlineChoose 11 answer:\newline(A) 11 and 52 \frac{5}{2} \newline(B) 74894 \frac{7}{4}-\frac{\sqrt{89}}{4} and\newline74+894 \frac{7}{4}+\frac{\sqrt{89}}{4} \newline(C) 72692 \frac{7}{2}-\frac{\sqrt{69}}{2} and\newline72+692 \frac{7}{2}+\frac{\sqrt{69}}{2} \newline(D) 72892 \frac{7}{2}-\frac{\sqrt{89}}{2} and\newline72+892 \frac{7}{2}+\frac{\sqrt{89}}{2}

Full solution

Q. If 2x27x5=0 2 x^{2}-7 x-5=0 , what are the values of x x ?\newlineChoose 11 answer:\newline(A) 11 and 52 \frac{5}{2} \newline(B) 74894 \frac{7}{4}-\frac{\sqrt{89}}{4} and\newline74+894 \frac{7}{4}+\frac{\sqrt{89}}{4} \newline(C) 72692 \frac{7}{2}-\frac{\sqrt{69}}{2} and\newline72+692 \frac{7}{2}+\frac{\sqrt{69}}{2} \newline(D) 72892 \frac{7}{2}-\frac{\sqrt{89}}{2} and\newline72+892 \frac{7}{2}+\frac{\sqrt{89}}{2}
  1. Use Quadratic Formula: Use the quadratic formula x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} where a=2a = 2, b=7b = -7, and c=5c = -5.
  2. Calculate Discriminant: Calculate the discriminant b24ac=(7)24(2)(5)=49+40=89b^2 - 4ac = (-7)^2 - 4(2)(-5) = 49 + 40 = 89.
  3. Plug into Formula: Plug the discriminant into the quadratic formula: x=7±8922x = \frac{7 \pm \sqrt{89}}{2 \cdot 2}.
  4. Simplify Expression: Simplify the expression: x=7±894x = \frac{7 \pm \sqrt{89}}{4}.
  5. Find Solutions: The solutions are x=74894x = \frac{7}{4} - \frac{\sqrt{89}}{4} and x=74+894x = \frac{7}{4} + \frac{\sqrt{89}}{4}.

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