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Fernando factored 45y^(6) as (9y^(3))(5y^(3)). Salma factored 45y^(6) as (3y)(15y^(5)). Which of them factored 45y^(6) correctly? Choose 1 answer: (A) Only Fernando (B) Only Salma (c) Both Fernando and Salma (D) Neither Fernando nor Salma

Fernando factored 45y6 45 y^{6} as (9y3)(5y3) \left(9 y^{3}\right)\left(5 y^{3}\right) .\newlineSalma factored 45y6 45 y^{6} as (3y)(15y5) (3 y)\left(15 y^{5}\right) .\newlineWhich of them factored 45y6 45 y^{6} correctly?\newlineChoose 11 answer:\newline(A) Only Fernando\newline(B) Only Salma\newline(C) Both Fernando and Salma\newline(D) Neither Fernando nor Salma

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Q. Fernando factored 45y6 45 y^{6} as (9y3)(5y3) \left(9 y^{3}\right)\left(5 y^{3}\right) .\newlineSalma factored 45y6 45 y^{6} as (3y)(15y5) (3 y)\left(15 y^{5}\right) .\newlineWhich of them factored 45y6 45 y^{6} correctly?\newlineChoose 11 answer:\newline(A) Only Fernando\newline(B) Only Salma\newline(C) Both Fernando and Salma\newline(D) Neither Fernando nor Salma
  1. Analyze Fernando's factorization: Analyze Fernando's factorization.\newlineFernando factored 45y645y^{6} as (9y3)(5y3)(9y^{3})(5y^{3}). Let's check if this factorization is correct by multiplying the factors back together.\newline(9y3)(5y3)=9×5×y3+3=45y6(9y^{3})(5y^{3}) = 9 \times 5 \times y^{3+3} = 45y^{6}.\newlineThis is the original expression, so Fernando's factorization is correct.
  2. Analyze Salma's factorization: Analyze Salma's factorization.\newlineSalma factored 45y645y^{6} as (3y)(15y5)(3y)(15y^{5}). Let's check if this factorization is correct by multiplying the factors back together.\newline(3y)(15y5)=3×15×y1+5=45y6(3y)(15y^{5}) = 3 \times 15 \times y^{1+5} = 45y^{6}.\newlineThis is also the original expression, so Salma's factorization is correct as well.
  3. Determine correct answer: Determine which answer choice is correct based on the previous steps.\newlineSince both Fernando and Salma factored 45y645y^{6} correctly, the correct answer is (C) Both Fernando and Salma.

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