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After 24 hours, 
30% of a 25 milligram dose of a new antibiotic remains in the body. Which of the following functions, 
M, models the amount of the antibiotic (in milligrams) that remains in the body after 
h hours?
Choose 1 answer:
(A) 
M(h)=30*(0.3)^((h)/( 24))
(B) 
M(h)=25*(0.3)^((h)/( 24))
(c) 
M(h)=25*(0.3)^(h)
(D) 
M(h)=25*(0.7)^((h)/( 24))

After 2424 hours, 30% 30 \% of a 2525 milligram dose of a new antibiotic remains in the body. Which of the following functions, M M , models the amount of the antibiotic (in milligrams) that remains in the body after h h hours?\newlineChoose 11 answer:\newline(A) M(h)=30(0.3)h24 M(h)=30 \cdot(0.3)^{\frac{h}{24}} \newline(B) M(h)=25(0.3)h24 M(h)=25 \cdot(0.3)^{\frac{h}{24}} \newline(C) M(h)=25(0.3)h M(h)=25 \cdot(0.3)^{h} \newline(D) M(h)=25(0.7)h24 M(h)=25 \cdot(0.7)^{\frac{h}{24}}

Full solution

Q. After 2424 hours, 30% 30 \% of a 2525 milligram dose of a new antibiotic remains in the body. Which of the following functions, M M , models the amount of the antibiotic (in milligrams) that remains in the body after h h hours?\newlineChoose 11 answer:\newline(A) M(h)=30(0.3)h24 M(h)=30 \cdot(0.3)^{\frac{h}{24}} \newline(B) M(h)=25(0.3)h24 M(h)=25 \cdot(0.3)^{\frac{h}{24}} \newline(C) M(h)=25(0.3)h M(h)=25 \cdot(0.3)^{h} \newline(D) M(h)=25(0.7)h24 M(h)=25 \cdot(0.7)^{\frac{h}{24}}
  1. Identify Decay Model: We need to find a function that models the decay of the antibiotic in the body over time. We know that after 2424 hours, 30%30\% of the initial dose remains. This means that the amount of antibiotic decreases to 30%30\% of its initial amount every 2424 hours. We can use an exponential decay function to model this.
  2. Exponential Decay Function: The general form of an exponential decay function is M(h)=M0×(decay_rate)(h/time_period)M(h) = M_0 \times (\text{decay\_rate})^{(h / \text{time\_period})}, where M0M_0 is the initial amount, decay_rate\text{decay\_rate} is the percentage that remains after each time period, and time_period\text{time\_period} is the length of the time period after which the decay_rate\text{decay\_rate} is applied.
  3. Substitute Values: In this case, M0M_0 is the initial dose, which is 2525 milligrams. The decay_rate\text{decay\_rate} is 30%30\%, or 0.30.3, since 30%30\% of the antibiotic remains after 2424 hours. The time_period\text{time\_period} is 2424 hours, as this is the period after which the decay_rate\text{decay\_rate} is applied.
  4. Final Exponential Decay Function: Substituting these values into the general form of the exponential decay function, we get M(h)=25×(0.3)h24M(h) = 25 \times (0.3)^{\frac{h}{24}}. This matches option (B) from the given choices.

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