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A=(pir^(2)theta)/(360)
The given equation can be used to find the area, 
A, of a sector of a circle of radius, 
r, where 
theta is the sector's central angle in degrees. Which of the following correctly shows the circle sector's radius in terms of the area of the sector and the central angle?
Choose 1 answer:
(A) 
r=sqrt((360 A)/(pi theta))
(B) 
r=(360 A)/(pi r theta)
(c) 
r=sqrt((pi theta)/(360 A))
(D) 
r=(pi theta)/(360 Ar)

A=πr2θ360 A=\frac{\pi r^{2} \theta}{360} \newlineThe given equation can be used to find the area, A A , of a sector of a circle of radius, r r , where θ \theta is the sector's central angle in degrees. Which of the following correctly shows the circle sector's radius in terms of the area of the sector and the central angle?\newlineChoose 11 answer:\newline(A) r=360Aπθ r=\sqrt{\frac{360 A}{\pi \theta}} \newline(B) r=360Aπrθ r=\frac{360 A}{\pi r \theta} \newline(C) r=πθ360A r=\sqrt{\frac{\pi \theta}{360 A}} \newline(D) r=πθ360Ar r=\frac{\pi \theta}{360 A r}

Full solution

Q. A=πr2θ360 A=\frac{\pi r^{2} \theta}{360} \newlineThe given equation can be used to find the area, A A , of a sector of a circle of radius, r r , where θ \theta is the sector's central angle in degrees. Which of the following correctly shows the circle sector's radius in terms of the area of the sector and the central angle?\newlineChoose 11 answer:\newline(A) r=360Aπθ r=\sqrt{\frac{360 A}{\pi \theta}} \newline(B) r=360Aπrθ r=\frac{360 A}{\pi r \theta} \newline(C) r=πθ360A r=\sqrt{\frac{\pi \theta}{360 A}} \newline(D) r=πθ360Ar r=\frac{\pi \theta}{360 A r}
  1. Write formula for area: Write down the given formula for the area of a sector of a circle.\newlineThe given formula is A=πr2θ360 A = \frac{\pi r^2 \theta}{360} , where A A is the area of the sector, r r is the radius of the circle, and θ \theta is the central angle in degrees.
  2. Isolate term r2r^2: Isolate the term r2r^2 in the formula to solve for rr.\newlineTo isolate r2r^2, multiply both sides of the equation by 360360 and divide by πθ\pi\theta.\newline360A=πr2θ360A = \pi r^2\theta\newliner2=360Aπθr^2 = \frac{360A}{\pi\theta}
  3. Solve for r: Solve for r by taking the square root of both sides of the equation.\newliner=(360Aπθ)r = \sqrt{\left(\frac{360A}{\pi\theta}\right)}
  4. Check answer choices: Check the answer choices to see which one matches the derived formula.\newlineThe correct answer choice that matches the derived formula is:\newliner=(360Aπθ) r = \sqrt{\left(\frac{360A}{\pi\theta}\right)}

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