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A circle in the 
xy-plane has the equation

(x-0.8)^(2)+(y-5.2)^(2)=1.69". "
How long is the radius of the circle?

A circle in the xy x y -plane has the equation\newline(x0.8)2+(y5.2)2=1.69 (x-0.8)^{2}+(y-5.2)^{2}=1.69 \text {. } \newlineHow long is the radius of the circle?

Full solution

Q. A circle in the xy x y -plane has the equation\newline(x0.8)2+(y5.2)2=1.69 (x-0.8)^{2}+(y-5.2)^{2}=1.69 \text {. } \newlineHow long is the radius of the circle?
  1. Circle Standard Form: The equation of a circle in the standard form is (xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2, where (h,k)(h, k) is the center of the circle and rr is the radius. In the given equation, (x0.8)2+(y5.2)2=1.69(x - 0.8)^2 + (y - 5.2)^2 = 1.69, we can see that it is already in standard form with h=0.8h = 0.8, k=5.2k = 5.2, and r2=1.69r^2 = 1.69.
  2. Find Radius: To find the radius rr, we need to take the square root of r2r^2. The given value for r2r^2 is 1.691.69. Therefore, we calculate rr as the square root of 1.691.69.
  3. Calculate Radius: Calculating the square root of 1.691.69 gives us r=1.69r = \sqrt{1.69}. \newlineThe square root of 1.691.69 is 1.31.3. \newlineSo, the radius of the circle is 1.31.3 units.

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