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What is $6 + \left( \frac{4}{a} \right) + \left( \frac{b}{3} \right)$ when $a = 4$ and $b = 3$ ?

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Algebra 2

Solve quadratic inequalities

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More problems from Solve quadratic inequalities

Question

-10 x-3 \geq 8 x+4

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Which of the following best describes the solutions to the inequality shown?

\newline

Choose

1

answer:

\newline

x \leq-\frac{7}{18}

\newline

(B)

x \leq-\frac{7}{2}

\newline

(C)

x \leq-\frac{1}{18}

\newline

(D)

x \geq-\frac{7}{18}

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Posted 10 months ago

Question

-12 x<-72

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Which of the following best describes the solutions to the inequality shown?

\newline

Choose

1

answer:

\newline

(A)

x<6

\newline

(B)

x>6

\newline

(C)

x<\frac{1}{6}

\newline

(D)

x>\frac{1}{6}

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Posted 10 months ago

Question

8 x+6<4 x+10

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Which of the following best describes the solutions to the inequality shown?

\newline

Choose

1

answer:

\newline

(A)

x<\frac{1}{3}

\newline

(B)

x<4

\newline

(C)

x<1

\newline

(D)

x>1

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Posted 10 months ago

Question

6 x-2<2 x+3

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Which of the following best describes the solutions to the inequality shown?

\newline

Choose

1

answer:

\newline

(A)

x<\frac{5}{4}

\newline

(B)

x>\frac{5}{4}

\newline

(C)

x<\frac{1}{4}

\newline

(D)

x<\frac{5}{8}

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Posted 10 months ago

Question

16<-4 x

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Which of the following best describes the solutions to the inequality shown?

\newline

Choose

1

answer:

\newline

(A)

x<-4

\newline

(B)

x>-4

\newline

(C)

x<-\frac{1}{4}

\newline

(D)

x>-\frac{1}{4}

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Posted 10 months ago

Question

Find

\lim _{x \rightarrow 4} \frac{2-\sqrt{4 x-12}}{x-4}

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Choose

1

answer:

\newline

(A)

2

\newline

(B)

1

\newline

(C)

-1

\newline

(D) The limit doesn't exist

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Posted 9 months ago

Question

Find

\lim _{x \rightarrow 2} \frac{x^{4}-4 x^{3}+4 x^{2}}{x-2}

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Choose

1

answer:

\newline

(A)

-4

\newline

(B)

0

\newline

(C)

4

\newline

(D) The limit doesn't exist

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Posted 9 months ago

Question

Let

f

be a continuous function on the closed interval

[-5,0]

, where

f(-5)=0

and

f(0)=5

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Which of the following is guaranteed by the Intermediate Value Theorem?

\newline

Choose

1

answer:

\newline

(A)

f(c)=-2

for at least one

c

between

0

and

5

\newline

(B)

f(c)=2

for at least one

c

between

0

and

5

\newline

(C)

f(c)=-2

for at least one

c

between

-5

and

0

\newline

(D)

f(c)=2

for at least one

c

between

-5

and

0

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Posted 9 months ago

Question

Let

g(x)=\tan (x)

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Can we use the intermediate value theorem to say the equation

g(x)=0

has a solution where

\frac{\pi}{4} \leq x \leq \frac{3 \pi}{4}

\newline

Choose

1

answer:

\newline

(A) No, since the function is not continuous on that interval.

\newline

(B) No, since

0

is not between

g\left(\frac{\pi}{4}\right)

and

g\left(\frac{3 \pi}{4}\right)

\newline

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Posted 9 months ago

Question

Let

g(x)=\cos (x)

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Can we use the intermediate value theorem to say the equation

g(x)=0.8

has a solution where

0 \leq x \leq \frac{\pi}{2}

\newline

Choose

1

answer:

\newline

(A) No, since the function is not continuous on that interval.

\newline

(B) No, since

0

8

is not between

g(0)

and

g\left(\frac{\pi}{2}\right)

\newline

Get tutor help

Posted 9 months ago

View all (25)

What is 6+(4a)+(b3) 6 + \left( \frac{4}{a} \right) + \left( \frac{b}{3} \right) 6+(a4​)+(3b​) when a=4 a = 4 a=4 and b=3 b = 3 b=3?

What is $6 + \left( \frac{4}{a} \right) + \left( \frac{b}{3} \right)$ when $a = 4$ and $b = 3$ ?