4 markers cost $7.04. Which equation would help determine the cost of 7 markers? Choose 1 answer: (A) (4)/(7)=($7.04)/(x) (B) (x)/(7)=(4)/($7.04) (C) (7)/(x)=($7.04)/(4) (D) (4)/(7)=(x)/($7.04) (E) None of the above

Given Cost Comparison: We are given the cost of 4 markers and we want to find the cost of 7 markers. This is a proportional relationship problem where the number of markers is directly proportional to the cost. We can set up a ratio comparing the cost of 4 markers to the cost of 7 markers.Setting Up Proportion: Let x represent the cost of 7 markers. We can set up the proportion as follows: the cost of 4 markers over 4 is equal to the cost of 7 markers over 7. This can be written as (4 markers / $7.04) = (7 markers / x).Cross-Multiplying: Simplify the proportion by cross-multiplying to solve for x. This gives us 4x = 7 * $7.04.Solving for x: Now we solve for x by dividing both sides of the equation by 4. This gives us x = (7 * $7.04) / 4.Final Calculation: Perform the calculation: x = (7 * $7.04) / 4 = $49.28 / 4 = $12.32. This is the cost of 7 markers.Correct Equation: The correct equation that represents this situation is (4 markers / $7.04) = (7 markers / x), which corresponds to option (A) (4/7) = ($7.04/x).

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4 markers cost
$7.04.
Which equation would help determine the cost of 7 markers?
Choose 1 answer:
(A)
(4)/(7)=($7.04)/(x)
(B)
(x)/(7)=(4)/($7.04)
(C)
(7)/(x)=($7.04)/(4)
(D)
(4)/(7)=(x)/($7.04)
(E) None of the above

$4$ markers cost $\$ 7.04$ . $\newline$ Which equation would help determine the cost of $7$ markers? $\newline$ Choose $1$ answer: $\newline$ (A) $\frac{4}{7}=\frac{\$ 7.04}{x}$ $\newline$ (B) $\frac{x}{7}=\frac{4}{\$ 7.04}$ $\newline$ (C) $\frac{7}{x}=\frac{\$ 7.04}{4}$ $\newline$ (D) $\frac{4}{7}=\frac{x}{\$ 7.04}$ $\newline$ (E) None of the above

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Math Problems

Algebra 1

Compare linear and exponential growth

Full solution

4

markers cost

\$ 7.04

\newline

Which equation would help determine the cost of

7

markers?

\newline

Choose

1

answer:

\newline

(A)

\frac{4}{7}=\frac{\$ 7.04}{x}

\newline

(B)

\frac{x}{7}=\frac{4}{\$ 7.04}

\newline

(C)

\frac{7}{x}=\frac{\$ 7.04}{4}

\newline

(D)

\frac{4}{7}=\frac{x}{\$ 7.04}

\newline

(E) None of the above

Given Cost Comparison: We are given the cost of $4$ markers and we want to find the cost of $7$ markers. This is a proportional relationship problem where the number of markers is directly proportional to the cost. We can set up a ratio comparing the cost of $4$ markers to the cost of $7$ markers.
Setting Up Proportion: Let $x$ represent the cost of $7$ markers. We can set up the proportion as follows: the cost of $4$ markers over $4$ is equal to the cost of $7$ markers over $7$ . This can be written as $(4 \text{ markers} / \$7.04) = (7 \text{ markers} / x)$ .
Cross-Multiplying: Simplify the proportion by cross-multiplying to solve for $x$ . This gives us $4x = 7 \times 7.04$ .
Solving for x: Now we solve for x by dividing both sides of the equation by $4$ . This gives us $x = (7 \times 7.04) / 4$ .
Final Calculation: Perform the calculation: $x = (7 \times \$(7.04)) / 4 = \$(49.28) / 4 = \$(12.32)$ . This is the cost of $7$ markers.
Correct Equation: The correct equation that represents this situation is $\frac{4 \text{ markers}}{\$7.04} = \frac{7 \text{ markers}}{x}$ , which corresponds to option (A) $\frac{4}{7} = \frac{\$7.04}{x}$ .