1-9b^(2)=0 What are the solutions to the given equation? Choose 1 answer: (A) b=-(1)/(3) and b=(1)/(3) (B) b=-(1)/(9) and b=(1)/(9) (C) b=(1)/(3) (D) b=(1)/(9)

Isolate term with variable b: First, let's isolate the term containing the variable b. 1 - 9b^2 = 0 Add 9b^2 to both sides to get: 1 = 9b^2Divide both sides by 9: Next, we divide both sides by 9 to solve for b^2. 1/9 = b^2Take square root of both sides: Now, we take the square root of both sides to solve for b. Remember that taking the square root of a number gives us two solutions, one positive and one negative. b = ±√(1/9)Simplify square root of 1/9: Simplify the square root of 1/9. b = ±1/3Find two solutions for b: We have found two solutions for b, which are b = 1/3 and b = -1/3.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

1-9b^(2)=0
What are the solutions to the given equation?
Choose 1 answer:
(A)
b=-(1)/(3) and
b=(1)/(3)
(B)
b=-(1)/(9) and
b=(1)/(9)
(C)
b=(1)/(3)
(D)
b=(1)/(9)

$1-9 b^{2}=0$ $\newline$ What are the solutions to the given equation? $\newline$ Choose $1$ answer: $\newline$ (A) $b=-\frac{1}{3}$ and $b=\frac{1}{3}$ $\newline$ (B) $b=-\frac{1}{9}$ and $b=\frac{1}{9}$ $\newline$ (C) $b=\frac{1}{3}$ $\newline$ (D) $b=\frac{1}{9}$

View step-by-step help

Home

Math Problems

Algebra 1

Compare linear and exponential growth

Full solution

1-9 b^{2}=0

\newline

What are the solutions to the given equation?

\newline

Choose

1

answer:

\newline

(A)

b=-\frac{1}{3}

and

b=\frac{1}{3}

\newline

(B)

b=-\frac{1}{9}

and

b=\frac{1}{9}

\newline

(C)

b=\frac{1}{3}

\newline

(D)

b=\frac{1}{9}

Isolate term with variable b: First, let's isolate the term containing the variable b. $\newline$ $1 - 9b^2 = 0$ $\newline$ Add $9b^2$ to both sides to get: $\newline$ $1 = 9b^2$
Divide both sides by $9$ : Next, we divide both sides by $9$ to solve for $b^2$ . $\newline$ $\frac{1}{9} = b^2$
Take square root of both sides: Now, we take the square root of both sides to solve for $b$ . Remember that taking the square root of a number gives us two solutions, one positive and one negative. $b = \pm\sqrt{\frac{1}{9}}$
Simplify square root of $\frac{1}{9}$ : Simplify the square root of $\frac{1}{9}$ . $b = \pm\frac{1}{3}$
Find two solutions for $b$ : We have found two solutions for $b$ , which are $b = \frac{$ $1$ }{ $3$ } and $b = -\frac{$ $1$ }{ $3$ }.