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{:[y=(4)/(7)x],[(2)/(3)x=y+(5)/(7)]:}
Consider the system of equations. If 
(x,y) is the solution to the system, then what is the value of 
y ?
Choose 1 answer:
(A) 
(2)/(21)
(B) 
(30)/(7)
(c) 
(15)/(2)
D None of the above

y=47x23x=y+57 \begin{array}{c} y=\frac{4}{7} x \\ \frac{2}{3} x=y+\frac{5}{7} \end{array} \newlineConsider the system of equations. If (x,y) (x, y) is the solution to the system, then what is the value of y y ?\newlineChoose 11 answer:\newline(A) 221 \frac{2}{21} \newline(B) 307 \frac{30}{7} \newline(C) 152 \frac{15}{2} \newline(D) None of the above

Full solution

Q. y=47x23x=y+57 \begin{array}{c} y=\frac{4}{7} x \\ \frac{2}{3} x=y+\frac{5}{7} \end{array} \newlineConsider the system of equations. If (x,y) (x, y) is the solution to the system, then what is the value of y y ?\newlineChoose 11 answer:\newline(A) 221 \frac{2}{21} \newline(B) 307 \frac{30}{7} \newline(C) 152 \frac{15}{2} \newline(D) None of the above
  1. Write down system of equations: First, let's write down the system of equations:\newliney=47xy = \frac{4}{7}x\newline23x=y+57\frac{2}{3}x = y + \frac{5}{7}\newlineWe need to solve this system to find the value of yy.
  2. Substitute expression for y: To solve the system, we can substitute the expression for y from the first equation into the second equation:\newline(23)x=(47)x+(57)(\frac{2}{3})x = (\frac{4}{7})x + (\frac{5}{7})\newlineNow we have an equation with just one variable, xx, which we can solve.
  3. Solve for x: Next, we'll solve for x. To do this, we need to get all the x terms on one side and the constants on the other side. We can start by multiplying both sides of the equation by 2121 (the least common multiple of 33 and 77) to clear the fractions:\newline21×(23)x=21×(47)x+21×(57)21 \times \left(\frac{2}{3}\right)x = 21 \times \left(\frac{4}{7}\right)x + 21 \times \left(\frac{5}{7}\right)\newlineThis simplifies to:\newline14x=12x+1514x = 12x + 15
  4. Isolate x terms: Now, we subtract 12x12x from both sides to isolate the x terms:\newline14x12x=1514x - 12x = 15\newline2x=152x = 15\newlineNext, we divide both sides by 22 to solve for x:\newlinex=152x = \frac{15}{2}
  5. Divide both sides by 22: Now that we have the value of xx, we can substitute it back into the first equation to find yy:\newliney=(47)(152)y = \left(\frac{4}{7}\right)\left(\frac{15}{2}\right)
  6. Substitute xx back into first equation: We multiply the numbers to find yy:
    y=(4×15)(7×2)y = \frac{(4 \times 15)}{(7 \times 2)}
    y=6014y = \frac{60}{14}
    y=307y = \frac{30}{7}
  7. Multiply to find y: The value of y is \frac{3030}{77}, which corresponds to answer choice (math)(B).

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