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-y^(2)(6x-y) Which of the following is equivalent to the given expression? Choose 1 answer: (A) -6x^(3)+x^(2)y (B) -6x^(2)y+y^(3) (C) -6xy^(2)+y^(3) (D) 6xy^(2)-y^(3)

−y2(6x−y) -y^{2}(6 x-y) \newlineWhich of the following is equivalent to the given expression?\newlineChoose 11 answer:\newline(A) −6x3+x2y -6 x^{3}+x^{2} y \newline(B) −6x2y+y3 -6 x^{2} y+y^{3} \newline(C) −6xy2+y3 -6 x y^{2}+y^{3} \newline(D) 6xy2−y3 6 x y^{2}-y^{3}

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Q. −y2(6x−y) -y^{2}(6 x-y) \newlineWhich of the following is equivalent to the given expression?\newlineChoose 11 answer:\newline(A) −6x3+x2y -6 x^{3}+x^{2} y \newline(B) −6x2y+y3 -6 x^{2} y+y^{3} \newline(C) −6xy2+y3 -6 x y^{2}+y^{3} \newline(D) 6xy2−y3 6 x y^{2}-y^{3}
  1. Distribute −y2-y^{2}: We need to distribute the term −y2-y^{2} across the terms inside the parentheses (6x−y)(6x-y). This is done by multiplying −y2-y^{2} with each term inside the parentheses separately.\newlineCalculation: −y2×6x+y2×y-y^{2} \times 6x + y^{2} \times y
  2. Multiply with 6x6x: Multiplying −y2-y^{2} by 6x6x gives us −6xy2-6xy^{2}. This is a straightforward multiplication of a constant with a variable term.\newlineCalculation: −y2×6x=−6xy2-y^{2} \times 6x = -6xy^{2}
  3. Multiply with −y-y: Multiplying y2y^{2} by −y-y gives us −y3-y^{3}. This is a multiplication of a variable term with itself, which results in raising the power by 11.\newlineCalculation: y2×−y=−y3y^{2} \times -y = -y^{3}
  4. Combine results: Combining the results from the previous steps, we get the final expression: −6xy2−y3-6xy^{2} - y^{3}.\newlineCalculation: −6xy2+(−y3)=−6xy2−y3-6xy^{2} + (-y^{3}) = -6xy^{2} - y^{3}

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