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(x+20)^(2)+(y-30)^(2)=225 A circle in the xy-plane has the equation shown. What is the y coordinate of the center of the circle?

(x+20)2+(y−30)2=225 (x+20)^{2}+(y-30)^{2}=225 \newlineA circle in the xy x y -plane has the equation shown. What is the y y coordinate of the center of the circle?

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Q. (x+20)2+(y−30)2=225 (x+20)^{2}+(y-30)^{2}=225 \newlineA circle in the xy x y -plane has the equation shown. What is the y y coordinate of the center of the circle?
  1. Identify standard form: Identify the standard form of a circle's equation and compare it to the given equation.\newlineThe standard form of a circle's equation is (x−h)2+(y−k)2=r2(x-h)^2 + (y-k)^2 = r^2, where (h,k)(h,k) is the center of the circle and rr is the radius.\newlineThe given equation is (x+20)2+(y−30)2=225(x+20)^2 + (y-30)^2 = 225.
  2. Determine h and k: Determine the values of h and k from the given equation.\newlineIn the given equation, (x+20)2(x+20)^2 corresponds to (x−h)2(x-h)^2 and (y−30)2(y-30)^2 corresponds to (y−k)2(y-k)^2.\newlineTherefore, h=−20h = -20 and k=30k = 30.
  3. Identify y-coordinate of center: Identify the y-coordinate of the center of the circle.\newlineSince kk represents the y-coordinate of the center of the circle, the y-coordinate is 3030.

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