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((x^(2))/(5)-x)/((x)/(9)+(1)/(3))

x25xx9+13 \frac{\frac{x^{2}}{5}-x}{\frac{x}{9}+\frac{1}{3}}

Full solution

Q. x25xx9+13 \frac{\frac{x^{2}}{5}-x}{\frac{x}{9}+\frac{1}{3}}
  1. Identify Given Expression: Identify the given expression and look for common denominators in the numerator and the denominator to combine terms.\newlineThe expression is (x25x)/(x9+13)\left(\frac{x^{2}}{5}-x\right)\left/\left(\frac{x}{9}+\frac{1}{3}\right)\right.
  2. Combine Common Denominators: Combine the terms in the denominator by finding a common denominator.\newlineThe common denominator for (x9)(\frac{x}{9}) and (13)(\frac{1}{3}) is 99.\newlineSo, (x9)+(13)(\frac{x}{9}) + (\frac{1}{3}) becomes (x9)+(39)(\frac{x}{9}) + (\frac{3}{9}) which simplifies to (x+39)(\frac{x+3}{9}).
  3. Rewrite with Simplified Denominator: Rewrite the expression with the simplified denominator.\newlineThe expression now is (x25x)/(x+39)\left(\frac{x^{2}}{5}-x\right)/\left(\frac{x+3}{9}\right).
  4. Multiply by Least Common Multiple: To simplify the complex fraction, multiply the numerator and the denominator by the least common multiple (LCM) of the denominators inside the complex fraction, which is 4545. So, we multiply (x25x)\left(\frac{x^{2}}{5}-x\right) and (x+39)\left(\frac{x+3}{9}\right) by 4545\frac{45}{45}.
  5. Multiply Numerator by 4545: Multiply the terms in the numerator by 4545.\newline(x2/5)45=9x2(x^{2}/5)\cdot 45 = 9x^2 and x45=45x-x\cdot 45 = -45x.\newlineSo, the numerator becomes 9x245x9x^2 - 45x.
  6. Multiply Denominator by 4545: Multiply the terms in the denominator by 4545. \newlinex+39×45=5(x+3)\frac{x+3}{9}\times 45 = 5(x+3).\newlineSo, the denominator becomes 5(x+3)5(x+3).
  7. Rewrite with Multiplied Numerator/Denominator: Rewrite the expression with the multiplied numerator and denominator.\newlineThe expression now is (9x245x)/(5(x+3))(9x^2 - 45x)/(5(x+3)).
  8. Factor Out Common Factor: Factor out the common factor in the numerator.\newlineThe common factor is 9x9x, so factor it out to get 9x(x5)9x(x - 5).\newlineThe expression now is 9x(x5)5(x+3)\frac{9x(x - 5)}{5(x+3)}.
  9. Check for Common Factors: Check for any common factors that can be canceled out from the numerator and the denominator.\newlineThere are no common factors to cancel out between 9x(x5)9x(x - 5) and 5(x+3)5(x+3).

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