(t+(1)/(3))(t+(2)/(3))=0 What are the solutions to the given equation? Choose 1 answer: (A) t=-(2)/(3) and t=-(1)/(3) (B) t=-(2)/(3) and t=(2)/(3) (C) t=-(1)/(3) and t=(1)/(3) (D) t=(1)/(3) and t=(2)/(3)

Given Equation: We are given the equation (t+(1)/(3))(t+(2)/(3))=0. To find the solutions, we will use the zero product property, which states that if the product of two factors is zero, then at least one of the factors must be zero.First Factor: Set the first factor equal to zero: t + (1/3) = 0. Solve for t by subtracting (1/3) from both sides of the equation. t = -(1/3)Second Factor: Set the second factor equal to zero: t + (2/3) = 0. Solve for t by subtracting (2/3) from both sides of the equation. t = -(2/3)Solutions: We have found two solutions to the equation: t = -(1/3) and t = -(2/3). These solutions correspond to choice (A).

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(t+(1)/(3))(t+(2)/(3))=0
What are the solutions to the given equation?
Choose 1 answer:
(A)
t=-(2)/(3) and
t=-(1)/(3)
(B)
t=-(2)/(3) and
t=(2)/(3)
(C)
t=-(1)/(3) and
t=(1)/(3)
(D)
t=(1)/(3) and
t=(2)/(3)

$\left(t+\frac{1}{3}\right)\left(t+\frac{2}{3}\right)=0$ $\newline$ What are the solutions to the given equation? $\newline$ Choose $1$ answer: $\newline$ (A) $t=-\frac{2}{3}$ and $t=-\frac{1}{3}$ $\newline$ (B) $t=-\frac{2}{3}$ and $t=\frac{2}{3}$ $\newline$ (C) $t=-\frac{1}{3}$ and $t=\frac{1}{3}$ $\newline$ (D) $t=\frac{1}{3}$ and $t=\frac{2}{3}$

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Algebra 1

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Full solution

\left(t+\frac{1}{3}\right)\left(t+\frac{2}{3}\right)=0

\newline

What are the solutions to the given equation?

\newline

Choose

1

answer:

\newline

(A)

t=-\frac{2}{3}

and

t=-\frac{1}{3}

\newline

(B)

t=-\frac{2}{3}

and

t=\frac{2}{3}

\newline

(C)

t=-\frac{1}{3}

and

t=\frac{1}{3}

\newline

(D)

t=\frac{1}{3}

and

t=\frac{2}{3}

Given Equation: We are given the equation $(t+\frac{1}{3})(t+\frac{2}{3})=0$ . To find the solutions, we will use the zero product property, which states that if the product of two factors is $0$ , then at least one of the factors must be $0$ .
First Factor: Set the first factor equal to zero: $t + \frac{1}{3} = 0$ . Solve for $t$ by subtracting $\frac{1}{3}$ from both sides of the equation. $\newline$ $t = -\frac{1}{3}$
Second Factor: Set the second factor equal to zero: $t + \frac{2}{3} = 0$ . Solve for $t$ by subtracting $\frac{2}{3}$ from both sides of the equation. $\newline$ $t = -\frac{2}{3}$
Solutions: We have found two solutions to the equation: $t = -\left(\frac{1}{3}\right)$ and $t = -\left(\frac{2}{3}\right)$ . These solutions correspond to choice $(A)$ .