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{:[h(t)=-10 t+6],[h(◻)=-44]:}

h(t)=−10t+6h(□)=−44 \begin{array}{l}h(t)=-10 t+6 \\ h(\square)=-44\end{array}

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Full solution

Q. h(t)=−10t+6h(□)=−44 \begin{array}{l}h(t)=-10 t+6 \\ h(\square)=-44\end{array}
  1. Identify function and value: Identify the given function and the value we need to find.\newlineWe are given the function h(t)=−10t+6h(t) = -10t + 6 and we need to find the value of ′t′'t' when h(t)=−44h(t) = -44.
  2. Set up equation with given value: Set up the equation with the given h(t) h(t) value.\newlineWe need to solve the equation −10t+6=−44 -10t + 6 = -44 .
  3. Isolate term with 't': Subtract 66 from both sides of the equation to isolate the term with 't'.\newline−10t+6−6=−44−6-10t + 6 - 6 = -44 - 6\newlineThis simplifies to −10t=−50-10t = -50.
  4. Solve for 't': Divide both sides of the equation by −10-10 to solve for 't'.\newline−10t/−10=−50/−10-10t / -10 = -50 / -10\newlineThis simplifies to t=5t = 5.

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