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Let’s check out your problem:
g
(
x
)
=
9
x
−
2
h
(
x
)
=
3
x
2
+
2
x
\begin{array}{l} g(x)=9 x-2 \\ h(x)=3 x^{2}+2 x \end{array}
g
(
x
)
=
9
x
−
2
h
(
x
)
=
3
x
2
+
2
x
\newline
Write
h
(
g
(
x
)
)
h(g(x))
h
(
g
(
x
))
as an expression in terms of
x
x
x
.
\newline
h
(
g
(
x
)
)
=
h(g(x))=
h
(
g
(
x
))
=
View step-by-step help
Home
Math Problems
Algebra 1
Compare linear, exponential, and quadratic growth
Full solution
Q.
g
(
x
)
=
9
x
−
2
h
(
x
)
=
3
x
2
+
2
x
\begin{array}{l} g(x)=9 x-2 \\ h(x)=3 x^{2}+2 x \end{array}
g
(
x
)
=
9
x
−
2
h
(
x
)
=
3
x
2
+
2
x
\newline
Write
h
(
g
(
x
)
)
h(g(x))
h
(
g
(
x
))
as an expression in terms of
x
x
x
.
\newline
h
(
g
(
x
)
)
=
h(g(x))=
h
(
g
(
x
))
=
Plug into
h
(
x
)
h(x)
h
(
x
)
:
Now let's plug
g
(
x
)
g(x)
g
(
x
)
into
h
(
x
)
h(x)
h
(
x
)
:
h
(
g
(
x
)
)
=
h
(
9
x
−
2
)
=
3
(
9
x
−
2
)
2
+
2
(
9
x
−
2
)
h(g(x)) = h(9x - 2) = 3(9x - 2)^2 + 2(9x - 2)
h
(
g
(
x
))
=
h
(
9
x
−
2
)
=
3
(
9
x
−
2
)
2
+
2
(
9
x
−
2
)
.
Square the binomial:
Next, we need to square the binomial
(
9
x
−
2
)
2
(9x - 2)^2
(
9
x
−
2
)
2
. This is
(
9
x
−
2
)
(
9
x
−
2
)
(9x - 2)(9x - 2)
(
9
x
−
2
)
(
9
x
−
2
)
.
Combine like terms:
Let's do the multiplication:
(
9
x
−
2
)
(
9
x
−
2
)
=
81
x
2
−
18
x
−
18
x
+
4
(9x - 2)(9x - 2) = 81x^2 - 18x - 18x + 4
(
9
x
−
2
)
(
9
x
−
2
)
=
81
x
2
−
18
x
−
18
x
+
4
.
Substitute back:
Now, combine like terms:
81
x
2
−
18
x
−
18
x
+
4
=
81
x
2
−
36
x
+
4
81x^2 - 18x - 18x + 4 = 81x^2 - 36x + 4
81
x
2
−
18
x
−
18
x
+
4
=
81
x
2
−
36
x
+
4
.
Distribute coefficients:
We'll substitute this back into the
h
(
g
(
x
)
)
h(g(x))
h
(
g
(
x
))
expression:
h
(
g
(
x
)
)
=
3
(
81
x
2
−
36
x
+
4
)
+
2
(
9
x
−
2
)
h(g(x)) = 3(81x^2 - 36x + 4) + 2(9x - 2)
h
(
g
(
x
))
=
3
(
81
x
2
−
36
x
+
4
)
+
2
(
9
x
−
2
)
.
Do the multiplication:
Now, distribute the
3
3
3
and the
2
2
2
:
h
(
g
(
x
)
)
=
3
×
81
x
2
−
3
×
36
x
+
3
×
4
+
2
×
9
x
−
2
×
2
h(g(x)) = 3 \times 81x^2 - 3 \times 36x + 3 \times 4 + 2 \times 9x - 2 \times 2
h
(
g
(
x
))
=
3
×
81
x
2
−
3
×
36
x
+
3
×
4
+
2
×
9
x
−
2
×
2
.
Combine like terms:
Let's do the multiplication:
h
(
g
(
x
)
)
=
243
x
2
−
108
x
+
12
+
18
x
−
4
h(g(x)) = 243x^2 - 108x + 12 + 18x - 4
h
(
g
(
x
))
=
243
x
2
−
108
x
+
12
+
18
x
−
4
.
Simplify expression:
Finally, combine like terms:
h
(
g
(
x
)
)
=
243
x
2
−
108
x
+
18
x
+
12
−
4
h(g(x)) = 243x^2 - 108x + 18x + 12 - 4
h
(
g
(
x
))
=
243
x
2
−
108
x
+
18
x
+
12
−
4
.
Simplify expression:
Finally, combine like terms:
h
(
g
(
x
)
)
=
243
x
2
−
108
x
+
18
x
+
12
−
4
h(g(x)) = 243x^2 - 108x + 18x + 12 - 4
h
(
g
(
x
))
=
243
x
2
−
108
x
+
18
x
+
12
−
4
.Simplify the expression:
h
(
g
(
x
)
)
=
243
x
2
−
90
x
+
8
h(g(x)) = 243x^2 - 90x + 8
h
(
g
(
x
))
=
243
x
2
−
90
x
+
8
.
More problems from Compare linear, exponential, and quadratic growth
Question
Jill bought a used motorcycle from a seller online for $1,200. The seller will charge her $5 a day to store the motorcycle at his house until she is able to pick it up. You can use a function to describe the total amount of money Jill will owe the seller if she waits
x
x
x
days to pick up the motorcycle.
\newline
Write an equation for the function. If it is linear, write it in the form
g
(
x
)
=
m
x
+
b
g(x) = mx + b
g
(
x
)
=
m
x
+
b
. If it is exponential, write it in the form
g
(
x
)
=
a
(
b
)
x
g(x) = a(b)^x
g
(
x
)
=
a
(
b
)
x
.
\newline
g
(
x
)
=
‾
g(x) = \underline{\hspace{3em}}
g
(
x
)
=
Get tutor help
Posted 8 months ago
Question
How does
f
(
t
)
=
−
2
t
−
7
f(t)=-2t-7
f
(
t
)
=
−
2
t
−
7
change over the interval from
t
=
−
7
t=-7
t
=
−
7
to
t
=
−
6
t=-6
t
=
−
6
?
\newline
Choices:
\newline
[
f(t) decreases by
2
]
\left[\text{f(t) decreases by } 2\right]
[
f(t) decreases by
2
]
\newline
[
f(t) increases by
2
]
\left[\text{f(t) increases by } 2\right]
[
f(t) increases by
2
]
\newline
[
f(t) increases by
200
%
]
\left[\text{f(t) increases by } 200\%\right]
[
f(t) increases by
200%
]
\newline
[
f(t) decreases by a factor of
2
]
\left[\text{f(t) decreases by a factor of } 2\right]
[
f(t) decreases by a factor of
2
]
Get tutor help
Posted 8 months ago
Question
How does
g
(
t
)
=
9
t
g(t)=9^t
g
(
t
)
=
9
t
change over the interval from
t
=
1
t=1
t
=
1
to
t
=
3
t=3
t
=
3
?
\newline
Choices:
\newline
[
g(t) decreases by a factor of
81
]
\left[\text{g(t) decreases by a factor of } 81\right]
[
g(t) decreases by a factor of
81
]
\newline
[
g(t) increases by a factor of
81
]
\left[\text{g(t) increases by a factor of } 81\right]
[
g(t) increases by a factor of
81
]
\newline
[
g(t) increases by
18
%
]
\left[\text{g(t) increases by } 18\%\right]
[
g(t) increases by
18%
]
\newline
[
g(t) decreases by
9
%
]
\left[\text{g(t) decreases by } 9\%\right]
[
g(t) decreases by
9%
]
Get tutor help
Posted 8 months ago
Question
Both of these functions grow as
x
x
x
gets larger and larger. Which function eventually exceeds the other?
\newline
Choices:
\newline
(
A
)
f
(
x
)
=
8
x
+
3.3
(A)f(x) = 8x + 3.3
(
A
)
f
(
x
)
=
8
x
+
3.3
\newline
(
B
)
g
(
x
)
=
3.
3
x
−
5
(B)g(x) = 3.3^x - 5
(
B
)
g
(
x
)
=
3.
3
x
−
5
Get tutor help
Posted 9 months ago
Question
Both of these functions grow as
x
x
x
gets larger and larger. Which function eventually exceeds the other?
\newline
Choices:
\newline
(
A
)
f
(
x
)
=
2
x
+
9
(A) \ f(x) = 2x + 9
(
A
)
f
(
x
)
=
2
x
+
9
\newline
(
B
)
g
(
x
)
=
2
x
(B)\ g(x) = 2^x
(
B
)
g
(
x
)
=
2
x
Get tutor help
Posted 9 months ago
Question
The functions
f
(
x
)
f(x)
f
(
x
)
and
g
(
x
)
g(x)
g
(
x
)
are differentiable.
\newline
The function
h
(
x
)
h(x)
h
(
x
)
is defined as:
h
(
x
)
=
g
(
x
)
f
(
x
)
h(x)=\frac{g(x)}{f(x)}
h
(
x
)
=
f
(
x
)
g
(
x
)
\newline
If
f
(
8
)
=
1
f(8)=1
f
(
8
)
=
1
,
f
′
(
8
)
=
−
6
f'(8)=-6
f
′
(
8
)
=
−
6
,
g
(
8
)
=
8
g(8)=8
g
(
8
)
=
8
, and
g
′
(
8
)
=
−
10
g'(8)=-10
g
′
(
8
)
=
−
10
, what is
h
′
(
8
)
h'(8)
h
′
(
8
)
?
\newline
Simplify any fractions.
\newline
h
′
(
8
)
=
h'(8)=
h
′
(
8
)
=
______
Get tutor help
Posted 8 months ago
Question
The functions
p
(
x
)
p(x)
p
(
x
)
and
q
(
x
)
q(x)
q
(
x
)
are differentiable.
\newline
The function
r
(
x
)
r(x)
r
(
x
)
is defined as:
r
(
x
)
=
p
(
x
)
q
(
x
)
r(x)= \frac{p(x)}{q(x)}
r
(
x
)
=
q
(
x
)
p
(
x
)
\newline
If
p
(
3
)
=
2
p(3)= 2
p
(
3
)
=
2
,
p
′
(
3
)
=
4
p'(3)= 4
p
′
(
3
)
=
4
,
q
(
3
)
=
6
q(3)= 6
q
(
3
)
=
6
, and
q
′
(
3
)
=
9
q'(3)= 9
q
′
(
3
)
=
9
, what is
r
′
(
3
)
r'(3)
r
′
(
3
)
?
\newline
Simplify any fractions.
\newline
r
′
(
3
)
=
r'(3)=
r
′
(
3
)
=
_____
Get tutor help
Posted 9 months ago
Question
The functions
u
(
x
)
u(x)
u
(
x
)
and
v
(
x
)
v(x)
v
(
x
)
are differentiable.
\newline
The function
w
(
x
)
w(x)
w
(
x
)
is defined as:
w
(
x
)
=
u
(
x
)
v
(
x
)
w(x)= \frac{u(x)}{v(x)}
w
(
x
)
=
v
(
x
)
u
(
x
)
\newline
If
u
(
5
)
=
3
u(5)= 3
u
(
5
)
=
3
,
u
′
(
5
)
=
−
2
u'(5)= -2
u
′
(
5
)
=
−
2
,
v
(
5
)
=
7
v(5)= 7
v
(
5
)
=
7
, and
v
′
(
5
)
=
1
v'(5)= 1
v
′
(
5
)
=
1
, what is
w
′
(
5
)
w'(5)
w
′
(
5
)
?
\newline
Simplify any fractions.
\newline
w
′
(
5
)
=
w'(5)=
w
′
(
5
)
=
_____
Get tutor help
Posted 9 months ago
Question
The functions
a
(
x
)
a(x)
a
(
x
)
and
b
(
x
)
b(x)
b
(
x
)
are differentiable.
\newline
The function
c
(
x
)
c(x)
c
(
x
)
is defined as:
c
(
x
)
=
a
(
x
)
b
(
x
)
c(x)= \frac{a(x)}{b(x)}
c
(
x
)
=
b
(
x
)
a
(
x
)
\newline
If
a
(
2
)
=
4
a(2)= 4
a
(
2
)
=
4
,
a
′
(
2
)
=
5
a'(2)= 5
a
′
(
2
)
=
5
,
b
(
2
)
=
1
b(2)= 1
b
(
2
)
=
1
, and
b
′
(
2
)
=
−
3
b'(2)= -3
b
′
(
2
)
=
−
3
, what is
c
′
(
2
)
c'(2)
c
′
(
2
)
?
\newline
Simplify any fractions.
\newline
c
′
(
2
)
=
c'(2)=
c
′
(
2
)
=
_____
Get tutor help
Posted 9 months ago
Question
The functions
m
(
x
)
m(x)
m
(
x
)
and
n
(
x
)
n(x)
n
(
x
)
are differentiable.
\newline
The function
o
(
x
)
o(x)
o
(
x
)
is defined as:
o
(
x
)
=
m
(
x
)
n
(
x
)
o(x)= \frac{m(x)}{n(x)}
o
(
x
)
=
n
(
x
)
m
(
x
)
\newline
If
m
(
7
)
=
2
m(7)= 2
m
(
7
)
=
2
,
m
′
(
7
)
=
−
1
m'(7)= -1
m
′
(
7
)
=
−
1
,
n
(
7
)
=
4
n(7)= 4
n
(
7
)
=
4
, and
n
′
(
7
)
=
8
n'(7)= 8
n
′
(
7
)
=
8
, what is
o
′
(
7
)
o'(7)
o
′
(
7
)
?
\newline
Simplify any fractions.
\newline
o
′
(
7
)
=
o'(7)=
o
′
(
7
)
=
_____
Get tutor help
Posted 9 months ago
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