f(x)=3x2+4x−2g(x)=7x2−bx+3Iff(x)−g(x)=−4x2+6x−5for all values of x where b is a constant, then what is the value of b ?Choose 1 answer:(A) −10(B) −2(C) 2(D) 10
Q. f(x)=3x2+4x−2g(x)=7x2−bx+3Iff(x)−g(x)=−4x2+6x−5for all values of x where b is a constant, then what is the value of b ?Choose 1 answer:(A) −10(B) −2(C) 2(D) 10
Given Functions: We are given two functions:f(x)=3x2+4x−2g(x)=7x2−bx+3And we know that:f(x)−g(x)=−4x2+6x−5To find the value of b, we need to subtract g(x) from f(x) and compare the result to the given expression for f(x)−g(x).
Subtracting f(x) and g(x): Let's perform the subtraction:f(x)−g(x)=(3x2+4x−2)−(7x2−bx+3)Simplify the expression by distributing the negative sign and combining like terms:f(x)−g(x)=3x2+4x−2−7x2+bx−3f(x)−g(x)=−4x2+(4+b)x−5
Comparing Coefficients: Now we compare the coefficients of the resulting expression with the given expression for f(x)−g(x):−4x2+(4+b)x−5=−4x2+6x−5The coefficients of x2 and the constant terms are already equal on both sides, so we only need to compare the coefficients of x:4+b=6
Solving for b: To find the value of b, we solve the equation:4+b=6Subtract 4 from both sides:b=6−4b=2
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