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{:[f(t)=(t)/(t-8)],[h(t)=-2t]:} Evaluate. f(h(-5))=

f(t)=tt−8h(t)=−2t \begin{array}{l} f(t)=\frac{t}{t-8} \\ h(t)=-2 t \end{array} \newlineEvaluate.\newlinef(h(−5))= f(h(-5))=

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Q. f(t)=tt−8h(t)=−2t \begin{array}{l} f(t)=\frac{t}{t-8} \\ h(t)=-2 t \end{array} \newlineEvaluate.\newlinef(h(−5))= f(h(-5))=
  1. Evaluate h(−5)h(-5): First, we need to evaluate h(−5)h(-5).\newlineh(t)=−2th(t) = -2t\newlineh(−5)=−2(−5)=10h(-5) = -2(-5) = 10
  2. Substitute value into f(t)f(t): Now that we have h(−5)=10h(-5) = 10, we can substitute this value into the function f(t)f(t).\newlinef(t)=tt−8f(t) = \frac{t}{t - 8}\newlinef(10)=1010−8=102=5f(10) = \frac{10}{10 - 8} = \frac{10}{2} = 5

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