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${:[f(a)=(a+2)^(2)],[g(a)=5a+4]:} Evaluate. g(f(-2))=$

$\begin{array}{l} f(a)=(a+2)^{2} \\ g(a)=5 a+4 \end{array}$ $\newline$ Evaluate. $\newline$ $g(f(-2))=$

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Compare linear and exponential growth

Full solution

Q.

\begin{array}{l} f(a)=(a+2)^{2} \\ g(a)=5 a+4 \end{array}

\newline

Evaluate.

\newline

g(f(-2))=

Find $f(-2)$ : First, let's find $f(-2)$ .
$f(a) = (a + 2)^2$
$f(-2) = (-2 + 2)^2$
$f(-2) = (0)^2$
$f(-2) = 0$
Plug into $g(a)$ : Now, let's plug $f(-2)$ into $g(a)$ . $\newline$ $g(a) = 5a + 4$ $\newline$ $g(f(-2)) = 5 \times f(-2) + 4$ $\newline$ $g(f(-2)) = 5 \times 0 + 4$ $\newline$ $g(f(-2)) = 0 + 4$ $\newline$ $g(f(-2)) = 4$

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