{:[E=[[5,3],[-2,1],[4,1]]" and "],[D=[[-2,-1],[5,0]]]:} Let H=ED. Find H. H=

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{:[E=[[5,3],[-2,1],[4,1]]" and "],[D=[[-2,-1],[5,0]]]:} Let  H=ED. Find  H.  H=

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Matrix Multiplication: Matrix multiplication involves taking the rows of the first matrix (E) and the columns of the second matrix (D) and performing dot products to get the entries of the resulting matrix (H). The dimensions of E are 3x2 and the dimensions of D are 2x2. Since the number of columns in E is equal to the number of rows in D, we can multiply these matrices. The resulting matrix H will have dimensions 3x2.Entry in H[1,1]: To find the entry in the first row and first column of H, we take the dot product of the first row of E with the first column of D. H[1,1] = (5 * -2) + (3 * 5) = -10 + 15 = 5.Entry in H[1,2]: To find the entry in the first row and second column of H, we take the dot product of the first row of E with the second column of D. H[1,2] = (5 * -1) + (3 * 0) = -5 + 0 = -5.Entry in H[2,1]: To find the entry in the second row and first column of H, we take the dot product of the second row of E with the first column of D. H[2,1] = (-2 * -2) + (1 * 5) = 4 + 5 = 9.Entry in H[2,2]: To find the entry in the second row and second column of H, we take the dot product of the second row of E with the second column of D. H[2,2] = (-2 * -1) + (1 * 0) = 2 + 0 = 2.Entry in H[3,1]: To find the entry in the third row and first column of H, we take the dot product of the third row of E with the first column of D. H[3,1] = (4 * -2) + (1 * 5) = -8 + 5 = -3.Entry in H[3,2]: To find the entry in the third row and second column of H, we take the dot product of the third row of E with the second column of D. H[3,2] = (4 * -1) + (1 * 0) = -4 + 0 = -4.

$\begin{array}{l} \mathrm{E}=\left[\begin{array}{rr} 5 & 3 \\ -2 & 1 \\ 4 & 1 \end{array}\right] \text { and } \mathrm{D}=\left[\begin{array}{rr} -2 & -1 \\ 5 & 0 \end{array}\right] \end{array}$ $\newline$ Let $\mathrm{H}=\mathrm{ED}$ . Find $\mathrm{H}$ . $\newline$ $\mathbf{H}=$

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