{:[E=[[3,5],[-1,1]]" and "],[A=[[-2,2,3],[3,5,-2]]]:} Let H=EA. Find H. H=

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{:[E=[[3,5],[-1,1]]" and "],[A=[[-2,2,3],[3,5,-2]]]:} Let  H=EA. Find  H.  H=

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Matrix Product Calculation: To find the matrix product H = EA, we need to perform matrix multiplication. The matrix E is a 2x2 matrix, and matrix A is a 2x3 matrix. The resulting matrix H will be a 2x3 matrix. We will calculate the entries of H by taking the dot product of the rows of E with the columns of A.Calculate H[1,1]: First, we calculate the entry in the first row and first column of H (H[1,1]). This is the dot product of the first row of E with the first column of A: H[1,1] = (3 * -2) + (5 * 3) = -6 + 15 = 9.Calculate H[1,2]: Next, we calculate the entry in the first row and second column of H (H[1,2]). This is the dot product of the first row of E with the second column of A: H[1,2] = (3 * 2) + (5 * 5) = 6 + 25 = 31.Calculate H[1,3]: Now, we calculate the entry in the first row and third column of H (H[1,3]). This is the dot product of the first row of E with the third column of A: H[1,3] = (3 * 3) + (5 * -2) = 9 - 10 = -1.Calculate H[2,1]: We move on to the second row and first column of H (H[2,1]). This is the dot product of the second row of E with the first column of A: H[2,1] = (-1 * -2) + (1 * 3) = 2 + 3 = 5.Calculate H[2,2]: Next, we calculate the entry in the second row and second column of H (H[2,2]). This is the dot product of the second row of E with the second column of A: H[2,2] = (-1 * 2) + (1 * 5) = -2 + 5 = 3.Calculate H[2,3: Finally, we calculate the entry in the second row and third column of H (H[2,3]). This is the dot product of the second row of E with the third column of A: H[2,3] = (-1 * 3) + (1 * -2) = -3 - 2 = -5.

$\begin{array}{l} E=\left[\begin{array}{rr} 3 & 5 \\ -1 & 1 \end{array}\right] \text { and } A=\left[\begin{array}{rrr} -2 & 2 & 3 \\ 3 & 5 & -2 \end{array}\right] \end{array}$ $\newline$ Let $\mathrm{H}=\mathrm{EA}$ . Find $\mathrm{H}$ . $\newline$ $\mathbf{H}=$

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