(dy)/(dx)=(1)/(x) and y(e)=-2. y(e^(3))=

Integrate and solve equation: Integrate both sides of the equation (dy)/(dx)=(1)/(x) to find y(x). ∫(dy) = ∫(1/x) dx y = ln|x| + CFind constant using initial condition: Substitute x=e to find the constant C using the initial condition y(e)=-2. -2 = ln|e| + C -2 = 1 + C C = -3Write general solution: Write the general solution for y(x) with the found constant C. y(x) = ln|x| - 3Substitute x=e^3: Substitute x=e^(3) into the general solution to find y(e^(3)). y(e^(3)) = ln|e^(3)| - 3 y(e^(3)) = 3ln|e| - 3Simplify expression: Simplify the expression since ln|e|=1. y(e^(3)) = 3(1) - 3 y(e^(3)) = 3 - 3Calculate final value: Calculate the final value of y(e^(3)). y(e^(3)) = 0

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(dy)/(dx)=(1)/(x) and
y(e)=-2.

y(e^(3))=

$\frac{d y}{d x}=\frac{1}{x}$ and $y(e)=-2$ . $\newline$ $y\left(e^{3}\right)=$

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Algebra 2

Csc, sec, and cot of special angles

Full solution

\frac{d y}{d x}=\frac{1}{x}

and

y(e)=-2

\newline

y\left(e^{3}\right)=

Integrate and solve equation: Integrate both sides of the equation $\frac{dy}{dx}=\frac{1}{x}$ to find $y(x)$ . $\int dy = \int \frac{1}{x} dx$ $y = \ln|x| + C$
Find constant using initial condition: Substitute $x=e$ to find the constant $C$ using the initial condition $y(e)=-2$ . $\newline$ $-2 = \ln|e| + C$ $\newline$ $-2 = 1 + C$ $\newline$ $C = -3$
Write general solution: Write the general solution for $y(x)$ with the found constant $C$ . $\newline$ $y(x) = \ln|x| - 3$
Substitute $x=e^3$ : Substitute $x=e^{3}$ into the general solution to find $y(e^{3})$ .
$y(e^{3}) = \ln|e^{3}| - 3$
$y(e^{3}) = 3\ln|e| - 3$
Simplify expression: Simplify the expression since $\ln|e|=1$ . $\newline$ $y(e^{3}) = 3(1) - 3$ $\newline$ $y(e^{3}) = 3 - 3$
Calculate final value: Calculate the final value of $y(e^{3})$ . $y(e^{3}) = 0$