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(d)/(dx)[cos(x)x^(2)]=

ddx[cos(x)x2]= \frac{d}{d x}\left[\cos (x) x^{2}\right]=

Full solution

Q. ddx[cos(x)x2]= \frac{d}{d x}\left[\cos (x) x^{2}\right]=
  1. Apply Product Rule: Use the product rule for differentiation, which states that (ddx)[uv]=uv+uv(\frac{d}{dx})[u*v] = u'v + uv', where u=cos(x)u = \cos(x) and v=x2v = x^2.
  2. Differentiate uu: Differentiate u=cos(x)u = \cos(x) to get u=sin(x)u' = -\sin(x).
  3. Differentiate vv: Differentiate v=x2v = x^2 to get v=2xv' = 2x.
  4. Apply Product Rule Formula: Plug uu', vv, uu, and vv' into the product rule formula: (sin(x))(x2)+(cos(x))(2x)(-\sin(x))(x^2) + (\cos(x))(2x).
  5. Simplify Expression: Simplify the expression: x2sin(x)+2xcos(x)-x^2 \sin(x) + 2x \cos(x).

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