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(d) 
(8c^(3))/(6(c+d))÷(2c^(2))/(3c+3d)

(d) 8c36(c+d)÷2c23c+3d \frac{8 c^{3}}{6(c+d)} \div \frac{2 c^{2}}{3 c+3 d}

Full solution

Q. (d) 8c36(c+d)÷2c23c+3d \frac{8 c^{3}}{6(c+d)} \div \frac{2 c^{2}}{3 c+3 d}
  1. Identify & Rewrite Division: Identify the given expression and rewrite the division as multiplication by the reciprocal of the second fraction.\newline(8c3)/(6(c+d))÷(2c2)/(3c+3d)=(8c3)/(6(c+d))×(3c+3d)/(2c2)(8c^{3})/(6(c+d)) \div (2c^{2})/(3c+3d) = (8c^{3})/(6(c+d)) \times (3c+3d)/(2c^{2})
  2. Simplify Coefficients & Variables: Simplify the coefficients and variables where possible.\newlineFirst, notice that 88 and 66 can be simplified by dividing both by 22, and 3c+3d3c+3d can be factored to 3(c+d)3(c+d).\newline8c36(c+d)×3c+3d2c2=4c33(c+d)×3(c+d)c2\frac{8c^{3}}{6(c+d)} \times \frac{3c+3d}{2c^{2}} = \frac{4c^{3}}{3(c+d)} \times \frac{3(c+d)}{c^{2}}
  3. Cancel Common Terms: Cancel out the common terms in the numerator and the denominator.\newlineThe (c+d)(c+d) terms cancel out, and we are left with:\newline4c33(c+d)×3(c+d)c2=4c31×1c2=4c3c2\frac{4c^{3}}{3(c+d)} \times \frac{3(c+d)}{c^{2}} = \frac{4c^{3}}{1} \times \frac{1}{c^{2}} = \frac{4c^{3}}{c^{2}}
  4. Simplify Remaining Expression: Simplify the remaining expression by subtracting the exponents of cc. When dividing like bases, subtract the exponents: c3c2=c32=c1=c\frac{c^{3}}{c^{2}} = c^{3-2} = c^{1} = c. 4c3c2=4c\frac{4c^{3}}{c^{2}} = 4c

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