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( 2 points) Calculate the molar concentrations of the unknown ionized product of water and its 
pH. Indicate whether these solutions are neutral, acidic or basic.






[H_(3)O^(+)]

[OH^(-)]

pH
Acidic/basic/neutral



1.3 ×10^(-13)

7.7 ×10^(-2)
13
basic



1.00 ×10^(-6)

99. ( 22 points) Calculate the molar concentrations of the unknown ionized product of water and its pH \mathrm{pH} . Indicate whether these solutions are neutral, acidic or basic.\newline\begin{tabular}{|c|c|c|c|}\newline\hline[H3O+] \left[\mathrm{H}_{3} \mathrm{O}^{+}\right] & {[OH] \left[\mathrm{OH}^{-}\right] } & pH \mathrm{pH} & Acidic/basic/neutral \\\newline\hline 1.3×1013 1.3 \times 10^{-13} & 7.7×102 7.7 \times 10^{-2} & 1313 & basic \\\newline\hline 1.00×106 1.00 \times 10^{-6} & & & \\\newline\hline\newline\end{tabular}

Full solution

Q. 99. ( 22 points) Calculate the molar concentrations of the unknown ionized product of water and its pH \mathrm{pH} . Indicate whether these solutions are neutral, acidic or basic.\newline\begin{tabular}{|c|c|c|c|}\newline\hline[H3O+] \left[\mathrm{H}_{3} \mathrm{O}^{+}\right] & {[OH] \left[\mathrm{OH}^{-}\right] } & pH \mathrm{pH} & Acidic/basic/neutral \\\newline\hline 1.3×1013 1.3 \times 10^{-13} & 7.7×102 7.7 \times 10^{-2} & 1313 & basic \\\newline\hline 1.00×106 1.00 \times 10^{-6} & & & \\\newline\hline\newline\end{tabular}
  1. Analyze Data for First Solution: Step 11: Analyze the given data for the first solution.\newlineGiven: [H3O+]=1.3×1013M[H_3O^+] = 1.3 \times 10^{-13} \, \text{M}, [OH]=7.7×102M[OH^-] = 7.7 \times 10^{-2} \, \text{M}, pH=13\text{pH} = 13.\newlineCheck if the product of [H_3O^+]\(\newline) and \$[OH^-]\(\newline\)) equals \$10^{-14}\) (the ion product of water at \(25\)\(\degree\)C).\(\newline\)Calculation: \((1.3 \times 10^{-13}) \times (7.7 \times 10^{-2}) = 1.001 \times 10^{-14}\).
  2. Determine Solution Nature: Step \(2\): Determine the nature of the solution based on pH. \(\newline\)\(pH = 13\), which is greater than \(7\).\(\newline\)This indicates a basic solution.
  3. Analyze Data for Second Solution: Step \(3\): Analyze the given data for the second solution.\(\newline\)Given: \([\text{H}_3\text{O}^+] = 1.00 \times 10^{-6} \, \text{M}\).\(\newline\)To find \([\text{OH}^-]\), use the ion product of water.\(\newline\)Calculation: \([\text{OH}^-] = 10^{-14} / [\text{H}_3\text{O}^+] = 10^{-14} / 1.00 \times 10^{-6} = 1.00 \times 10^{-8} \, \text{M}\).

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