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Let’s check out your problem:
−
2
⋅
(
4
+
4
i
)
=
-2 \cdot(4+4 i)=
−
2
⋅
(
4
+
4
i
)
=
\newline
Your answer should be a complex number in the form
a
+
b
i
a+b i
a
+
bi
where
a
a
a
and
b
b
b
are real numbers.
View step-by-step help
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Math Problems
Precalculus
Write equations of cosine functions using properties
Full solution
Q.
−
2
⋅
(
4
+
4
i
)
=
-2 \cdot(4+4 i)=
−
2
⋅
(
4
+
4
i
)
=
\newline
Your answer should be a complex number in the form
a
+
b
i
a+b i
a
+
bi
where
a
a
a
and
b
b
b
are real numbers.
Performing the multiplication:
Now we perform the multiplication for each term separately.
\newline
−
2
×
4
=
−
8
-2 \times 4 = -8
−
2
×
4
=
−
8
\newline
(
−
2
)
×
4
i
=
−
8
i
(-2) \times 4i = -8i
(
−
2
)
×
4
i
=
−
8
i
Combining the results:
Combine the results of the multiplication to get the final complex number.
\newline
−
8
+
(
−
8
i
)
=
−
8
−
8
i
-8 + (-8i) = -8 - 8i
−
8
+
(
−
8
i
)
=
−
8
−
8
i
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Your answer should be a complex number in the form
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bi
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Your answer should be a complex number in the form
a
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i
a+b i
a
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bi
where
a
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b
are real numbers.
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bi
where
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are real numbers.
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i
⋅
(
12
−
i
)
=
\newline
Your answer should be a complex number in the form
a
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b
i
a+b i
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bi
where
a
a
a
and
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b
are real numbers.
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\newline
Your answer should be a complex number in the form
a
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i
a+b i
a
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bi
where
a
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and
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are real numbers.
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3
i
⋅
(
8
i
+
5
)
=
\newline
Your answer should be a complex number in the form
a
+
b
i
a+b i
a
+
bi
where
a
a
a
and
b
b
b
are real numbers.
Get tutor help
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Question
−
12
⋅
(
8
−
2
i
)
=
-12 \cdot(8-2 i)=
−
12
⋅
(
8
−
2
i
)
=
\newline
Your answer should be a complex number in the form
a
+
b
i
a+b i
a
+
bi
where
a
a
a
and
b
b
b
are real numbers.
Get tutor help
Posted 10 months ago
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