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15*(-4i+2)= Your answer should be a complex number in the form a+bi where a and b are real numbers.

15⋅(−4i+2)= 15 \cdot(-4 i+2)= \newlineYour answer should be a complex number in the form a+bi a+b i where a a and b b are real numbers.

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Q. 15⋅(−4i+2)= 15 \cdot(-4 i+2)= \newlineYour answer should be a complex number in the form a+bi a+b i where a a and b b are real numbers.
  1. Multiply real part by 1515: Multiply the real part of the complex number by 1515.\newlineThe real part of the complex number is 22. Multiplying this by 1515 gives us 3030.\newlineCalculation: 15×2=3015 \times 2 = 30
  2. Multiply imaginary part by 1515: Multiply the imaginary part of the complex number by 1515.\newlineThe imaginary part of the complex number is \(-4i＂). Multiplying this by 1515 gives us \(-60i＂).\newlineCalculation: \(15 \times (−4-4i) = −60-60i＂)
  3. Combine results to form final complex number: Combine the results from Step 11 and Step 22 to form the final complex number.\newlineThe real part is 3030 and the imaginary part is −60i-60i. Therefore, the final complex number is 30−60i30 - 60i.\newlineCalculation: 30+(−60i)=30−60i30 + (-60i) = 30 - 60i

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