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-4*(20 i+10)=
Your answer should be a complex number in the form 
a+bi where 
a and 
b are real numbers.

4(20i+10)= -4 \cdot(20 i+10)= \newlineYour answer should be a complex number in the form a+bi a+b i where a a and b b are real numbers.

Full solution

Q. 4(20i+10)= -4 \cdot(20 i+10)= \newlineYour answer should be a complex number in the form a+bi a+b i where a a and b b are real numbers.
  1. Multiply real part by 4-4: Multiply the real part of the complex number by 4-4.\newlineThe real part of the complex number 20i+1020i + 10 is 1010. Multiplying this by 4-4 gives us:\newline4×10=40-4 \times 10 = -40
  2. Multiply imaginary part by 4-4: Multiply the imaginary part of the complex number by -4").\(\newlineThe imaginary part of the complex number \$20i + 10\) is \(20i"). Multiplying this by \$-4\) gives us:\(\newline\)\(\(-4\) \times \(20\)i = \(-80\)i")
  3. Combine results for final answer: Combine the results from Step \(1\) and Step \(2\) to get the final answer.\(\newline\)The real part from Step \(1\) is \(-40\) and the imaginary part from Step \(2\) is \(-80i\). Combining these gives us the final complex number:\(\newline\)\(-40 - 80i\)

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