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14*(-2i+6)=
Your answer should be a complex number in the form
a+bi where
a and
b are real numbers.

$14 \cdot(-2 i+6)=$ $\newline$ Your answer should be a complex number in the form $a+b i$ where $a$ and $b$ are real numbers.

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Write equations of cosine functions using properties

Full solution

Q.

14 \cdot(-2 i+6)=

\newline

Your answer should be a complex number in the form

a+b i

where

a

and

b

are real numbers.

Multiply real part by $14$ : Multiply the real part of the complex number by $14$ . $\newline$ The real part of the complex number is $6$ . Multiplying this by $14$ gives us: $\newline$ $14 \times 6 = 84$
Multiply imaginary part by $14$ : Multiply the imaginary part of the complex number by $14$ . $\newline$ The imaginary part of the complex number is \(-2i＂). Multiplying this by $14$ gives us: $\newline$ \(14 \times ( $-2$ i) = $-28$ i＂)
Combine results for final answer: Combine the results from Step $1$ and Step $2$ to get the final answer. $\newline$ The real part from Step $1$ is $84$ , and the imaginary part from Step $2$ is $-28i$ . Combining these gives us: $\newline$ $84 - 28i$

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