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10*(-6-9i)= Your answer should be a complex number in the form a+bi where a and b are real numbers.

10⋅(−6−9i)= 10 \cdot(-6-9 i)= \newlineYour answer should be a complex number in the form a+bi a+b i where a a and b b are real numbers.

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Q. 10⋅(−6−9i)= 10 \cdot(-6-9 i)= \newlineYour answer should be a complex number in the form a+bi a+b i where a a and b b are real numbers.
  1. Multiply real part by 1010: Multiply the real part of the complex number by 1010.\newlineWe have the real part of the complex number as -6＂). Multiplying this by 10 gives us:\(\newline\$10 \times (-6) = -60\)
  2. Multiply imaginary part by \(10\): Multiply the imaginary part of the complex number by \(10\).\(\newline\)The imaginary part of the complex number is \(-9i\). Multiplying this by \(10\) gives us:\(\newline\)\(10 \times (-9i) = -90i\)
  3. Combine results for final answer: Combine the results from Step \(1\) and Step \(2\) to get the final answer.\(\newline\)The real part from Step \(1\) is \(-60\) and the imaginary part from Step \(2\) is \(-90i\). Combining these gives us the final complex number:\(\newline\)\(-60 - 90i\)

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