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Powers with integer bases

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2 \times 10-7 \times 2=

Evaluate the following expression.

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8^{3}-9 \cdot 2 \div 3=

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7\times3-2\times5=

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2+2\div 2=

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43.396 \div 57.1=

0.195+89.1=

8.556+83=

63.284+27=

4.3+26.539=

5.58+0.712=

66.54+9.393=

48.5+0.433=

37.279+5.4=

25+1.847=

54+6.598=

57.2+3.768=

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59.7-0.446=

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47.3-0.883=

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57.348-6.332=

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39.1-0.794=

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14.3-0.595=

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22.7-0.662=

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83.9-0.584=

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6.658-3=

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9.85-0.282=

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52.389-7.1=

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51.6-0.624=

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47.2-6.307=

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2.23-0.107=

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2.83-0.772=

71.2 \times 0.58=

1.84 \times 25.1=

0.74 \times 0.422=

11 \times 20.9 =

623 \times 5.1=

162 \times 0.967=

77.2 \times 0.272=

0.905 \times 0.234=

0.345 \times 83.8=

83.6 \times 85.5=

Solve. Write your answer as an integer or a fraction in simplest form.

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10 = 5^x

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x=

Solve. Write your answer as an integer or a fraction in simplest form.

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5 = 3^x

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x=

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2^2 =