Evaluate. 52.389-7.1=

Aligning numbers vertically: Align the numbers vertically by their decimal points for subtraction. 52.389 - 7.1Adding trailing zeros: Add trailing zeros to 7.1 to match the number of decimal places in 52.389. 52.389 - 7.100Subtracting from right to left: Subtract the numbers starting from the rightmost digit, moving towards the left. 2 - 0 = 2 8 - 0 = 8 3 - 1 = 2 5 - 7 cannot be done, so we need to borrow from the tens place.Borrowing from the tens place: After borrowing, the subtraction in the ones place is: 12 (from the borrow) - 7 = 5 And reduce the tens place by 1, so it becomes 4.Writing down the final result: Write down the final result of the subtraction. 52.389 - 7.100 --------- 45.289

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Math Problems

Algebra 1

Powers with integer bases

Full solution

Q. Evaluate.

\newline

52.389-7.1=

Aligning numbers vertically: Align the numbers vertically by their decimal points for subtraction. $\newline$ $52.389$ $\newline$ $- 7.1$
Adding trailing zeros: Add trailing zeros to $7.1$ to match the number of decimal places in $52.389$ . $\newline$ $\newline$ $52$ . $389$ $\newline$ - $7$ . $100$ $\newline$
Subtracting from right to left: Subtract the numbers starting from the rightmost digit, moving towards the left. $\newline$ $2 - 0 = 2$ $\newline$ $8 - 0 = 8$ $\newline$ $3 - 1 = 2$ $\newline$ $5 - 7$ cannot be done, so we need to borrow from the tens place.
Borrowing from the tens place: After borrowing, the subtraction in the ones place is: $\newline$ $12$ (from the borrow) $- 7 = 5$ $\newline$ And reduce the tens place by $1$ , so it becomes $4$ .
Writing down the final result: Write down the final result of the subtraction. $\newline$ $52.389$ $\newline$ $- 7.100$ $\newline$ $---------$ $\newline$ $45.289$