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y=x^(2)-2x-3
Find the vertex of the following parabola.

y=x22x3 y=x^{2}-2 x-3 \newlineFind the vertex of the following parabola.

Full solution

Q. y=x22x3 y=x^{2}-2 x-3 \newlineFind the vertex of the following parabola.
  1. Calculate x-coordinate: To find the vertex of a parabola given by the equation y=ax2+bx+cy = ax^2 + bx + c, we can use the vertex formula x=b2ax = -\frac{b}{2a} for the x-coordinate of the vertex.\newlineIn our equation, a=1a = 1 and b=2b = -2.\newlineLet's calculate the x-coordinate of the vertex.\newlinex=(2)/(21)=22=1x = -(-2)/(2\cdot1) = \frac{2}{2} = 1
  2. Find y-coordinate: Now that we have the x-coordinate of the vertex, we can find the y-coordinate by substituting xx back into the original equation.y=(1)22(1)3=123=4y = (1)^2 - 2*(1) - 3 = 1 - 2 - 3 = -4
  3. Identify vertex point: We have found both coordinates of the vertex. The vertex of the parabola is at the point (1,4)(1, -4).

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