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Write the equation in standard form for the ellipse 3x2+y2−15=03x^2 + y^2 - 15 = 0.

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Full solution

Q. Write the equation in standard form for the ellipse 3x2+y2−15=03x^2 + y^2 - 15 = 0.
  1. Divide by 1515: Now, divide everything by 1515 to get the standard form of the ellipse. (x25)+(y215)=1(\frac{x^2}{5}) + (\frac{y^2}{15}) = 1
  2. Check standard form: Check if the equation looks like the standard form (x2/a2)+(y2/b2)=1(x^2/a^2) + (y^2/b^2) = 1, where a2a^2 and b2b^2 are the denominators.\newlineYep, it does.

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