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The equation of an ellipse is given below.

((x-5)^(2))/(3)+((y-7)^(2))/(6)=1
What are the foci of this ellipse?
Choose 1 answer:
(A) 
(5,7+sqrt3) and

(5,7-sqrt3)
(B) 
(-5,-7+sqrt3) and

(-5,-7-sqrt3)
(C) 
(-5+sqrt3,-7) and 
(-5-sqrt3,-7)
(D) 
(5+sqrt3,7) and

(5-sqrt3,7)

The equation of an ellipse is given below.\newline(x5)23+(y7)26=1 \frac{(x-5)^{2}}{3}+\frac{(y-7)^{2}}{6}=1 \newlineWhat are the foci of this ellipse?\newlineChoose 11 answer:\newline(A) (5,7+3) (5,7+\sqrt{3}) and (5,73) (5,7-\sqrt{3}) \newline(B) (5,7+3) (-5,-7+\sqrt{3}) and (5,73) (-5,-7-\sqrt{3}) \newline(C) (5+3,7) (-5+\sqrt{3},-7) and (53,7) (-5-\sqrt{3},-7) \newline(D) (5+3,7) (5+\sqrt{3}, 7) and (53,7) (5-\sqrt{3}, 7)

Full solution

Q. The equation of an ellipse is given below.\newline(x5)23+(y7)26=1 \frac{(x-5)^{2}}{3}+\frac{(y-7)^{2}}{6}=1 \newlineWhat are the foci of this ellipse?\newlineChoose 11 answer:\newline(A) (5,7+3) (5,7+\sqrt{3}) and (5,73) (5,7-\sqrt{3}) \newline(B) (5,7+3) (-5,-7+\sqrt{3}) and (5,73) (-5,-7-\sqrt{3}) \newline(C) (5+3,7) (-5+\sqrt{3},-7) and (53,7) (-5-\sqrt{3},-7) \newline(D) (5+3,7) (5+\sqrt{3}, 7) and (53,7) (5-\sqrt{3}, 7)
  1. Identify Center and Axes: Identify the center and lengths of the semi-major and semi-minor axes.\newlineThe given equation of the ellipse is (x5)23+(y7)26=1\frac{(x-5)^{2}}{3}+\frac{(y-7)^{2}}{6}=1. The standard form of an ellipse is (xh)2a2+(yk)2b2=1\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1, where (h,k)(h, k) is the center of the ellipse, aa is the length of the semi-major axis, and bb is the length of the semi-minor axis. For our ellipse, h=5h=5, k=7k=7, a2=3a^2=3, and b2=6b^2=6. Therefore, a=3a=\sqrt{3} and (xh)2a2+(yk)2b2=1\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 100.
  2. Determine Major Axis: Determine which axis is the major axis.\newlineSince a^2 < b^2, the major axis is along the y-direction. This means that the foci will be found by moving up and down from the center along the y-axis.
  3. Calculate Distance to Foci: Calculate the distance from the center to the foci. The distance cc from the center to each focus is given by the formula c2=b2a2c^2 = b^2 - a^2. Plugging in the values we have c2=63=3c^2 = 6 - 3 = 3. Therefore, c=3c = \sqrt{3}.
  4. Find Foci Coordinates: Find the coordinates of the foci.\newlineThe foci are located at (h,k±c)(h, k\pm c) since the major axis is vertical. Substituting the values we have, the foci are at (5,7±3)(5, 7\pm\sqrt{3}).
  5. Choose Correct Answer: Choose the correct answer.\newlineThe correct answer is (A) (5,7+3)(5, 7+\sqrt{3}) and (5,73)(5, 7-\sqrt{3}), since these are the coordinates we found for the foci.

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