What is the center of the ellipse ((x – 5)^2)/9 + ((y – 2)^2)/54 = 1? Write your answer in simplified, rationalized form. (______,______)

Identify Standard Form: Identify the standard form of the ellipse equation. The standard form of an ellipse equation is (x - h)^2/a^2 + (y - k)^2/b^2 = 1, where (h, k) is the center of the ellipse.Compare with Standard Form: Compare the given equation with the standard form. The given equation is ((x – 5)^2)/9 + ((y – 2)^2)/54 = 1. By comparing this with the standard form, we can see that h = 5 and k = 2.Write Center: Write down the center of the ellipse. The center of the ellipse is (h, k), which is (5, 2) in this case.

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What is the center of the ellipse $\left(\frac{(x - 5)^2}{9}\right) + \left(\frac{(y - 2)^2}{54}\right) = 1$ ? $\newline$ Write your answer in simplified, rationalized form. $\newline$ (__ , _)

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Algebra 2

Find the center, vertices, or co-vertices of an ellipse

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Q. What is the center of the ellipse

\left(\frac{(x - 5)^2}{9}\right) + \left(\frac{(y - 2)^2}{54}\right) = 1

\newline

Write your answer in simplified, rationalized form.

\newline

(________ , _______)

Identify Standard Form: Identify the standard form of the ellipse equation. $\newline$ The standard form of an ellipse equation is $(x - h)^2/a^2 + (y - k)^2/b^2 = 1$ , where $(h, k)$ is the center of the ellipse.
Compare with Standard Form: Compare the given equation with the standard form. $\newline$ The given equation is $\frac{(x - 5)^2}{9} + \frac{(y - 2)^2}{54} = 1$ . By comparing this with the standard form, we can see that $h = 5$ and $k = 2$ .
Write Center: Write down the center of the ellipse. $\newline$ The center of the ellipse is $(h, k)$ , which is $(5, 2)$ in this case.