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Write an equation to describe the sequence below. Use 
n to represent the position of a term in the sequence, where 
n=1 for the first term.

8,16,32,dots
Write your answer using decimals and integers.

a_(n)=◻(◻)^(n-1)

Write an equation to describe the sequence below. Use n n to represent the position of a term in the sequence, where n=1 n=1 for the first term.\newline8,16,32, 8,16,32, \ldots \newlineWrite your answer using decimals and integers.\newlinean=()n1 a_{n}=\square(\square)^{n-1}

Full solution

Q. Write an equation to describe the sequence below. Use n n to represent the position of a term in the sequence, where n=1 n=1 for the first term.\newline8,16,32, 8,16,32, \ldots \newlineWrite your answer using decimals and integers.\newlinean=()n1 a_{n}=\square(\square)^{n-1}
  1. Sequence Type: We have the sequence: 8,16,32,8, 16, 32, \ldots\newlineIs the given sequence geometric or arithmetic?\newline8,16,32,8, 16, 32, \ldots\newlineHere, each term is multiplied by a common ratio.\newlineThe given sequence is geometric.
  2. Determine Values: Determine the values of a1a_{1} (the first term) and rr (the common ratio) of the sequence.\newlineFirst term: a1=8a_{1} = 8\newlineCommon ratio: r=168=2r = \frac{16}{8} = 2
  3. Find Expression: Now that we have a1=8a_{1} = 8 and r=2r = 2, we can determine an expression to describe ana_{n}. Substitute 88 for a1a_{1} and 22 for rr into the formula for the nth term of a geometric sequence. an=a1×(r)n1a_{n} = a_{1} \times (r)^{n - 1} an=8×(2)n1a_{n} = 8 \times (2)^{n - 1}

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