Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

What is the period of

y=-2sin((2)/(3)x-4)?
Give an exact value.
units

What is the period of\newliney=2sin(23x4)? y=-2 \sin \left(\frac{2}{3} x-4\right) ? \newlineGive an exact value.\newlineunits

Full solution

Q. What is the period of\newliney=2sin(23x4)? y=-2 \sin \left(\frac{2}{3} x-4\right) ? \newlineGive an exact value.\newlineunits
  1. Identify Period Formula: The period of a sine function y=asin(bxc)+dy = a \cdot \sin(bx - c) + d is given by the formula T=2πbT = \frac{2\pi}{|b|}. In the given function y=2sin(23x4)y = -2\sin\left(\frac{2}{3}x - 4\right), we need to identify the value of bb to determine the period.
  2. Determine Coefficient Value: The coefficient bb in the function y=2sin(23x4)y = -2\sin(\frac{2}{3}x - 4) is 23\frac{2}{3}. This is the value that affects the period of the sine function.
  3. Calculate Period Formula: Using the formula for the period T=2πbT = \frac{2\pi}{|b|}, we substitute bb with 23\frac{2}{3} to find the period of the given function. Therefore, T=2π23T = \frac{2\pi}{|\frac{2}{3}|}.
  4. Simplify Expression: To calculate the period, we simplify the expression T=2π/(23)T = 2\pi / (\frac{2}{3}). This is equivalent to T=2π×(32)T = 2\pi \times (\frac{3}{2}) because dividing by a fraction is the same as multiplying by its reciprocal.
  5. Find Period Value: Multiplying 2π2\pi by (3/2)(3/2) gives us T=3πT = 3\pi. This is the period of the function y=2sin(23x4)y = -2\sin\left(\frac{2}{3}x - 4\right).

More problems from Find the sum of an arithmetic series