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What is the period of

y=8cos(5pi x+(3pi)/(2))-9?
Give an exact value.
units

What is the period of\newliney=8cos(5πx+3π2)9? y=8 \cos \left(5 \pi x+\frac{3 \pi}{2}\right)-9 ? \newlineGive an exact value.\newlineunits

Full solution

Q. What is the period of\newliney=8cos(5πx+3π2)9? y=8 \cos \left(5 \pi x+\frac{3 \pi}{2}\right)-9 ? \newlineGive an exact value.\newlineunits
  1. Formula for cosine function period: The period of a cosine function of the form y=Acos(Bx+C)+Dy = A \cos(Bx + C) + D is given by the formula Period = 2πB\frac{2\pi}{|B|}. Here, AA is the amplitude, BB is the frequency, CC is the phase shift, and DD is the vertical shift.
  2. Identifying the value of B: Identify the value of B in the given function y = 88\cos(55\pi x + \frac{33\pi}{22}) - 99. The value of B is the coefficient of x inside the cosine function, which is 55\pi.
  3. Calculating the period: Calculate the period using the formula Period=2πB \text{Period} = \frac{2\pi}{|B|} . Substitute B B with 5π 5\pi .\newlinePeriod=2π5π=2π5π \text{Period} = \frac{2\pi}{|5\pi|} = \frac{2\pi}{5\pi} .
  4. Simplifying the expression: Simplify the expression for the period. Since π\pi is in both the numerator and the denominator, they cancel each other out.\newlinePeriod = 25\frac{2}{5}.
  5. Exact value of the period: The exact value of the period of the function y=8cos(5πx+3π2)9y = 8\cos(5\pi x + \frac{3\pi}{2}) - 9 is 25\frac{2}{5} units.

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