Which sign makes the statement true? 1.5 × 10^3 ? 1.50 × 10^3 Choices: (A)> (B)< (C)=

Analyze Expressions: Analyze the given expressions. We have 1.5 × 10^3 and 1.50 × 10^3. Are the base numbers the same or different? The base numbers are 1.5 and 1.50, which are equivalent because the trailing zero does not change the value of the number.Compare Exponents: Compare the exponents. Since the base numbers are equivalent, we compare the exponents to determine the relationship between the two expressions. The exponents in both expressions are 3. Since the exponents are the same, the expressions are equal. 1.5 × 10^3 = 1.50 × 10^3.Choose Correct Sign: Choose the correct sign. Based on the comparison, the correct sign to make the statement true is ＂=＂. So, 1.5 × 10^3 = 1.50 × 10^3.

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Which sign makes the statement true? $\newline$ $1.5 \times 10^3$ $\text{?}$ $1.50 \times 10^3$ $\newline$ Choices: $\newline$ (A) > $\newline$ (B) < $\newline$ (C) $=$

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Math Problems

Grade 8

Compare numbers written in scientific notation

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Q. Which sign makes the statement true?

\newline

1.5 \times 10^3

\text{?}

1.50 \times 10^3

\newline

Choices:

\newline

(A)

>

\newline

(B)

<

\newline

(C)

=

Analyze Expressions: Analyze the given expressions. $\newline$ We have $1.5 \times 10^3$ and $1.50 \times 10^3$ . $\newline$ Are the base numbers the same or different? $\newline$ The base numbers are $1.5$ and $1.50$ , which are equivalent because the trailing zero does not change the value of the number.
Compare Exponents: Compare the exponents. $\newline$ Since the base numbers are equivalent, we compare the exponents to determine the relationship between the two expressions. $\newline$ The exponents in both expressions are $3$ . $\newline$ Since the exponents are the same, the expressions are equal. $\newline$ $1.5 \times 10^3 = 1.50 \times 10^3$ .
Choose Correct Sign: Choose the correct sign. $\newline$ Based on the comparison, the correct sign to make the statement true is ＂ $=$ ＂. $\newline$ So, $1.5 \times 10^3 = 1.50 \times 10^3$ .