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Let’s check out your problem:
Which of the following is equivalent to
(
8
r
4
+
4
r
2
+
2
r
)
−
(
8
r
4
+
4
r
2
+
1
)
\left(8 r^{4}+4 r^{2}+2 r\right)-\left(8 r^{4}+4 r^{2}+1\right)
(
8
r
4
+
4
r
2
+
2
r
)
−
(
8
r
4
+
4
r
2
+
1
)
?
\newline
Choose
1
1
1
answer:
\newline
(A)
8
r
2
+
2
r
+
1
8 r^{2}+2 r+1
8
r
2
+
2
r
+
1
\newline
(B)
8
r
2
+
3
r
8 r^{2}+3 r
8
r
2
+
3
r
\newline
(C)
2
r
−
1
2 r-1
2
r
−
1
\newline
(D)
r
r
r
View step-by-step help
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Math Problems
Calculus
Find derivatives of using multiple formulae
Full solution
Q.
Which of the following is equivalent to
(
8
r
4
+
4
r
2
+
2
r
)
−
(
8
r
4
+
4
r
2
+
1
)
\left(8 r^{4}+4 r^{2}+2 r\right)-\left(8 r^{4}+4 r^{2}+1\right)
(
8
r
4
+
4
r
2
+
2
r
)
−
(
8
r
4
+
4
r
2
+
1
)
?
\newline
Choose
1
1
1
answer:
\newline
(A)
8
r
2
+
2
r
+
1
8 r^{2}+2 r+1
8
r
2
+
2
r
+
1
\newline
(B)
8
r
2
+
3
r
8 r^{2}+3 r
8
r
2
+
3
r
\newline
(C)
2
r
−
1
2 r-1
2
r
−
1
\newline
(D)
r
r
r
Subtract Polynomials:
Subtract the second polynomial from the first.
\newline
(
8
r
4
+
4
r
2
+
2
r
)
−
(
8
r
4
+
4
r
2
+
1
)
=
8
r
4
−
8
r
4
+
4
r
2
−
4
r
2
+
2
r
−
1
(8r^{4}+4r^{2}+2r) - (8r^{4}+4r^{2}+1) = 8r^{4} - 8r^{4} + 4r^{2} - 4r^{2} + 2r - 1
(
8
r
4
+
4
r
2
+
2
r
)
−
(
8
r
4
+
4
r
2
+
1
)
=
8
r
4
−
8
r
4
+
4
r
2
−
4
r
2
+
2
r
−
1
Combine Like Terms:
Combine like terms.
\newline
8
r
4
−
8
r
4
=
0
8r^{4} - 8r^{4} = 0
8
r
4
−
8
r
4
=
0
\newline
4
r
2
−
4
r
2
=
0
4r^{2} - 4r^{2} = 0
4
r
2
−
4
r
2
=
0
\newline
So, the expression simplifies to
2
r
−
1
2r - 1
2
r
−
1
Check Answer Choices:
Check the answer choices to see which one matches the simplified expression.
\newline
The correct answer is (C)
2
r
−
1
2r - 1
2
r
−
1
.
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lim
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x
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x
−
12
7
x
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answer:
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(B)
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7
7
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(C)
−
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−
1
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(D) The limit doesn't exist
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Find
lim
x
→
−
3
x
+
3
4
−
2
x
+
22
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lim
x
→
−
3
4
−
2
x
+
22
x
+
3
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1
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4
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lim
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1
answer:
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(A)
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5
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5
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Find
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x
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−
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x
3
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3
x
2
+
2
x
x
+
2
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lim
x
→
−
2
x
+
2
x
3
+
3
x
2
+
2
x
.
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Choose
1
1
1
answer:
\newline
(A)
6
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6
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(B)
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(C)
2
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Question
Find
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x
→
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2
cot
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(
x
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1
−
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(
x
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lim
x
→
2
π
1
−
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i
n
(
x
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o
t
2
(
x
)
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Choose
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1
1
answer:
\newline
(A)
−
1
-1
−
1
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(B)
−
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2
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(C)
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2
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Question
Find
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x
→
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2
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(
2
x
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cos
(
x
)
\lim _{x \rightarrow \frac{\pi}{2}} \frac{\sin (2 x)}{\cos (x)}
lim
x
→
2
π
c
o
s
(
x
)
s
i
n
(
2
x
)
.
\newline
Choose
1
1
1
answer:
\newline
(A)
1
2
\frac{1}{2}
2
1
\newline
(B)
1
1
1
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(C)
2
2
2
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Question
Find
lim
θ
→
π
4
cos
(
2
θ
)
2
cos
(
θ
)
−
1
\lim _{\theta \rightarrow \frac{\pi}{4}} \frac{\cos (2 \theta)}{\sqrt{2} \cos (\theta)-1}
lim
θ
→
4
π
2
c
o
s
(
θ
)
−
1
c
o
s
(
2
θ
)
.
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1
1
answer:
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2
2
2
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(B)
1
2
\frac{1}{2}
2
1
\newline
(C)
2
\sqrt{2}
2
\newline
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